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vovikov84 [41]
3 years ago
7

What is the slope-intercept equation for the following line? y=-x+

Mathematics
2 answers:
VikaD [51]3 years ago
6 0

Answer:

Step-by-step explanation:

y = (-1/2)x -3

the slope is m = -1/2 because to get to one point to another you go 1 down and 2 to the right

the y-intercept is where the line intersects the y-axis at point (0, -3)

abruzzese [7]3 years ago
5 0

Answer:

y=-1/2x-3

I hope this helps u :)

Step-by-step explanation:

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How do you write 36/100 as a fraction in simplest form?
maks197457 [2]

Answer:

Step-by-step explanation:

8 0
3 years ago
How many triangles can be constructed with side lengths of 7.2 cm, 6.9 cm, and 12.8 cm?
Alika [10]

Answer:

One triangle

Step-by-step explanation:

-The triangle's dimensions are defined and fixed.

-Given the fixed dimensions, only one unique triangle can be constructed.

-Hence, only one triangle of the dimensions 7.2cm, 6.9cm and 12.8 cm can be formed.

5 0
3 years ago
9.a )Explain why plane JKL is not an appropriate
VLD [36.1K]

Answer:

I will attach the missing drawing with the answer.

9.b)

Plane JKM

Plane JLM

Plane KLM

Step-by-step explanation:

The drawing for this question is missing. I will attach it with the answer.

9.a) Plane JKL is not an appropriate name for the plane because all of three points lie in the same line.

Through a line pass infinite planes. The plane JKL doesn't define a unique plane. That's why plane JKL isn't an appropriate name for the plane.

9.b) We can name the plane using three points that don't lie in the same line.

Three possible names for the plane are :

Plane JKM

Plane JLM

Plane KLM

6 0
3 years ago
A student walk 60m on a bearing
Katena32 [7]

Answer:

d = 234.6 m

Step-by-step explanation:

You can consider a system of coordinates with its origin at the beginning of the walk of the student.

When she start to walk, she is at (0,0)m. After her first walk, her coordinates are calculated by using the information about the incline and the distance that she traveled:

x_1=60cos28\°=52.97m\\\\y_1=60sin28\°=28.16m

she is at the coordinates (52.97 , 28.16)m.

Next, when she walks 180m to the east, her coordinates are:

(52.97+180 , 28.16)m = (232.97 , 28.16)m

To calculate the distance from the final point of the student to the starting point you use the Pythagoras generalization for the distance between two points:

d=\sqrt{(x-x_o)^2+(y-y_o)^2}\\\\x=232.97\\\\x_o=0\\\\y=28.16\\\\y_o=0\\\\d=\sqrt{(232.97-0)^2+(28.16-0)^2}m=234.6m

The displacement of the student on her complete trajectory was of 234.6m

8 0
3 years ago
PLEASE HELP!!!!!!What is the solution of the system?
AleksAgata [21]
Y=3x
or 
-6x + 2y= 0
hope this helps and maybe  brainly!
5 0
3 years ago
Read 2 more answers
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