Which of these formulas is NOT consistent with the guidelines for creating ionic compounds? Mark all that apply.

Hydrogen gas (a potential future fuel) can be formed by the reaction of methane with water according to the following equation:

Nastasia [14]

Answer:

The % yield of this reaction is 61.9 %

Explanation:

Step 1: Data given

Volume of methane = 25.0 L

Pressure of methane = 732 torr = 732 /760 atm = 0.9631579 atm

Temperature = 25.0 °C = 298 K

Volume of water vapor = 22.2 L

Pressure of water vapor = 704 torr = 704/760 atm = 0.92631579 atm

Temperature = 125 °C 398 K

The reaction produces 26.2 L hydrogen gas

Step 2: The balanced equation

CH4(g)+H2O(g)→CO(g)+3H2(g)

Step 3: Calculate moles methane

p*V = n*R*T

n =(p*V)/(R*T)

⇒with n = the moles of methane = TO BE DETERMINED

⇒with p= the pressure of methane = 732 torr = 0.9631579 atm

⇒with V = the volume of methane = 25.0 L

⇒with R = the gas constant =0.08206 L*atm/mol*K

⇒with T = the temperature = 298 K

n = (0.9631579 * 25.0) / (0.08206*298)

n = 0.984668 moles

Step 4: Calculate moles H2O

p*V = n*R*T

n =(p*V)/(R*T)

⇒with n = the moles of H2O= TO BE DETERMINED

⇒with p= the pressure of methane = 704 torr = 0.92631579 atm

⇒with V = the volume of methane = 22.2 L

⇒with R = the gas constant =0.08206 L*atm/mol*K

⇒with T = the temperature = 398 K

n = (0.92631579 * 22.2 )/(0.08206 * 398) = 0.62965 mol H2O

Step 5: Calculate moles H2

CH4(g) + H2O(g) ⇄ CO(g) + 3H2(g)

For 1 mol CH4 we need 1 mol H2O to produce 1 mol CO and 3 moles H2

H2O is the limiting reactant. It will completely be consumed. (0.62965 moles). Methane is in excess. There will react 0.62965 moles. There will remain 0.984668 - 0.62965 = 0.355018 moles methane

For 0.62965 moles H2O we'll have 3*0.62965 = 1.88895 moles H2

Step 6: Calculate volume H2

p*V = n*R*T

V= (n*R*T)/p

⇒with V = the volume of H2 = TO BE DETERMINED

⇒with n = the moles of H2 produced = 1.88895 moles

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 273K

⇒with p = the pressure of H2 = 1.0 atm

V = (1.88895 * 0.08206 * 273) / 1.0

V = 42.32 L

Step 7: Calculate the percent yield

% yield = (actual yield / theoretical yield) * 100 %

% yield = (26.2 / 42.32) * 100 %

% yield = 61.9 %

The % yield of this reaction is 61.9 %

8 0

4 years ago

The equilibrium constant, K., for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC13(E) Calculate the equilibrium

lord [1]

Answer:

The equilibrium concentration of $PCl_5=0.228 M$ .

The equilibrium concentration of $PCl_3=0.280 M -0.228 M=0.052M$ .

The equilibrium concentration of $Cl_2=0.280 M -0.228 M=0.052M$ .

Explanation:

Answer:

The equilibrium concentration of HCl is 0.01707 M.

Explanation:

Equilibrium constant of the reaction = $K_c=83.3$

Moles of $PCl_3 = 0.280 mol$

Concentration of $[PCl_3]=\frac{0.280 mol}{1.00 L}=0.280 M$

Moles of $Cl_ = 0.280 mol$

Concentration of $[Cl_2]=\frac{0.280 mol}{1.00 L}=0.280M$

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

Initial: 0.280 0.280 0

At eq'm: (0.280-x) (0.280-x) x

We are given:

$[PCl_3]_{eq}=(0.280-x)$

$[Cl_2]_{eq}=(0.280-x)$

$[PCl_5]_{eq}=x$

Calculating for 'x'. we get:

The expression of $K_{c}$ for above reaction follows:

$K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}$

Putting values in above equation, we get:

$83.3=\frac{x}{(0.280-x)\times (0.280-x)}$

On solving this quadratic equation we get:

x = 0.228, 0.344

0.228 M < 0.280 M< 0.344 M

x = 0.228 M

The equilibrium concentration of $PCl_5=0.228 M$ .

The equilibrium concentration of $PCl_3=0.280 M -0.228 M=0.052M$ .

The equilibrium concentration of $Cl_2=0.280 M -0.228 M=0.052M$ .

4 0

3 years ago

When does hydrogen first begin to fuse into helium in the star formation process?

valentina_108 [34]

Step one of the Hydrogen fusion process helium a nucleus of Deuterium is formed from two protons with the emission of an antielectron and a neutrino.

The fundamental Hydrogen fusion cycle includes 4 Hydrogen nuclei and two electrons and yields a Helium nucleus, two neutrinos and six photons. The principle series phase is the stage in development where the center temperature reaches the point for the fusion to begin. in this manner, the protons of hydrogen are converted into atoms of helium.

If the star is big sufficient to fuse hydrogen atoms into helium, it's going to enter the phase that our solar is in, referred to as the primary sequence section. a celebrity will enjoy most of its existence in the major series section. At this point nuclear fusion is turning hydrogen into helium.

A star isn't always absolutely a star until it is able to fuse hydrogen into helium. before that, they are called Protostars. A protostar is fashioned as gravity begins to tug the gases together right into a ball. This process is referred to as accretion.

Learn more about hydrogen here:-brainly.com/question/19813237

#SPJ4

8 0

2 years ago

Predict whether the equilibria I) CH4(g) + H2O(g) ⇀↽ CO(g) + 3 H2(g), ∆H◦ = +206 kJ II) 2 SO2(g) + O2 ⇀↽ 2 SO3(g), ∆H◦ = −198 kJ

Diano4ka-milaya [45]

Answer:

1. I shifts toward products and II shifts toward reactants.

Explanation:

Hello,

In his case, since the reaction I) is endothermic (positive ∆H°) and the reaction II) is exothermic (negative ∆H°):

- In the first case, the energy is understood as a reactant, so if the temperature increases, heat is added so the reaction will shift rightwards (towards products).

- In the second case, the energy is understood as a product, so if the temperature increases, heat is added so the reaction will shift leftwards (towards reactants).

Therefore, the answer is:

1. I shifts toward products and II shifts toward reactants.

Best regards.

6 0

3 years ago

What is the mass of 4.85 X 10^22 atoms of iron (Fe)?

ludmilkaskok [199]

Answer:

Mass = 4.5 g

Explanation:

Given data:

Number of atoms of iron = 4.85 ×10²² atoms

Mass of iron = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

4.85 × 10²² atoms of iron / 6.022 × 10²³ atoms × 1 mol

0.081 mol

Mass of iron:

Mass = number of moles × molar mass

Mass = 0.081 mol × 55.85 g/mol

Mass = 4.5 g

8 0

3 years ago