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insens350 [35]
3 years ago
13

An organism had 1,000 grams of carbon-14 (a radioactive form of carbon) in it when it died. How much remains after five half-liv

es?
Chemistry
1 answer:
Katarina [22]3 years ago
5 0

Answer:

After 5th half life the remaining mass is 31.25 g.

Explanation:

Given data:

Total mass of carbon-14 = 1000 g

Mass remain after 5 half lives = ?

Solution:

At time zero = 1000 g

At first half life = 1000 g/2 = 500 g

At second half life =  500 g/ 2= 250 g

At third half life = 250 g/ 2 = 125 g

At 4th half life = 125 g/2 = 62.5 g

At 5th half life = 62.5 g/2 = 31.25 g

Thus after 5th half life the remaining mass is 31.25 g.

You might be interested in
The reaction can be described using the equation: 2C2H25O24CO22H2O. How much C2H2is needed to react with 68.1 g of O2to produce
Sophie [7]

Answer:

22.13g

Explanation:

We'll begin by writing a balanced equation for the reaction. This is illustrated below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

Next, we'll calculate the mass of C2H2 and O2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of C2H2 = (12x2) + (2x1)

= 24 + 2 = 26g/mol

Mass of C2H2 that reacted from the balanced equation = 2 x 26 = 52g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 that reacted from the balanced equation = 5 x 32 = 160g

Now, we can obtain the mass of C2H2 that will react with 68.1g of O2 as follow:

From the balanced equation above,

52g of C2H2 reacted with 160g of O2.

Therefore, Xg of C2H2 will react with 68.1g of O2 i.e

Xg of C2H2 = (52x68.1)/160

Xg of C2H2 = 22.13g

Therefore, 22.13g of C2H2 is needed to react with 68.1g of O2

8 0
3 years ago
An isotope of cesium-137 has a half-life of 30 years. If 5.0g of cesium-137 decays over 60 years. How many grams will remain.
LenKa [72]

Answer:

1.25 gram of cesium-137 will remain.

Explanation:

Given data:

Half life of cesium-137 = 30 year

Mass of cesium-137 = 5.0 g

Mass remain after 60 years = ?

Solution:

Number of half lives passed = Time elapsed / half life

Number of half lives passed = 60 year / 30 year

Number of half lives passed = 2

At time zero = 5.0 g

At first half life = 5.0 g/2 = 2.5 g

At 2nd half life = 2.5 g/ 2 = 1.25 g

Thus. 1.25 gram of cesium-137 will remain.

6 0
3 years ago
Based on the activity series of metal, which reaction with water will not happen?
laila [671]

Answer:

B

Explanation:

B, H2O + Na The elements toward the bottom left corner of the periodic table are the metals that are the most active in the sense of being the most reactive. Lithium, sodium, and potassium all react with water,

5 0
3 years ago
what is a major drawback of using fossil fuels they warmn the planet they contain no greenohuse gases
Charra [1.4K]

The major drawback of fossil fuels is that they warm the planet i.e. they cause global warming.

The reaction typically gives off heat and light as well. The general equation for a complete combustion reaction is:

                                  Fuel + O2 → CO2 + H2O + ENERGY

<h3>Disadvantages of Fossil fuels</h3>

The term "fossil fuels" refers to flammable organic geologic formations, including dead organic matter that has been buried hundreds of feet beneath sediment.

  • Fossil fuel emissions include various oxides, such as carbon, nitrogen, and sulfate, which cause acid rain and harm the soil's fertility and water quality.
  • Both coal and petroleum burning discharge a significant amount of pollutants into the atmosphere, contributing to pollution levels.
  • Gases like carbon dioxide are released through the burning of fossil fuels, which aids in climate change.

To view similar questions on Fossil fuels, refer to:

brainly.com/question/14339391

#SPJ4

7 0
1 year ago
¿Qué pasaría si un organismo o animal fuera eliminado de una red alimentaria?
34kurt

Answer: Sí

Explanation: Sí

4 0
3 years ago
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