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3 years ago

What dose the T-cell attack

Chemistry

1 answer:

MAXImum [283]3 years ago

5 0

Answer:

killer T-cell find and destroy infected cells that have been turned into virus-making factories

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A metal is found that has a mass of 27g and will displace 6mL of water. Calculate its density and identify the metal.

melisa1 [442]

The density of metal = 4.5 g/ml, and the metal = Titanium

<h3>Further explanation </h3>

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

Density formula:

$\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}$

ρ = density

m = mass

v = volume

mass of metal=27 g

volume = 6 ml

The density :

$\tt \rho=\dfrac{27}{6}\\\\\rho=4.5~g/ml$

The metal with a density of 4.5 g/ml is Titanium

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3 years ago

What are your hobbies? F r e e P o i n t s

Lubov Fominskaja [6]

Answer: Quantum mechanics is a fundamental theory in physics that provides a description of the physical properties of nature at the scale of atoms and subatomic particles. It is the foundation of all quantum physics including quantum chemistry, quantum field theory, quantum technology, and quantum information science.

I making my page look smart :)

7 0

3 years ago

Read 2 more answers

Floods occur when rainfall or snowmelt exceeds the flow capacity of a river. True False

valina [46]

Id say true, as if it exceeds the flow capasity there would be to much water flowing,therefor causing a flood

3 0

3 years ago

PLEASE HELP!!!!! Calcium hydroxide is _____. an acid a base a neutral

Bingel [31]

I believe it is a base!

4 0

3 years ago

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The element iridium exists in nature as two isotopes: 191Ir has a mass of 190.9606 u, and 193Ir has a mass of 192.9629 u. The av

nlexa [21]

Answer: The percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope be 'x'. So, fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope will be '1 - x'

For $_{77}^{191}\textrm{Ir}$ isotope:

Mass of $_{77}^{191}\textrm{Ir}$ isotope = 190.9606 amu

Fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope = x

For $_{77}^{193}\textrm{Ir}$ isotope:

Mass of $_{77}^{193}\textrm{Ir}$ isotope = 192.9629 amu

Fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope = 1 - x

Average atomic mass of iridium = 192.22 amu

Putting values in equation 1, we get:

$192.22=[(190.9606\times x)+(192.9629\times (1-x))]\\\\x=0.3710$

Percentage abundance of $_{77}^{191}\textrm{Ir}$ isotope = $0.3710\times 100=37.10\%$

Percentage abundance of $_{77}^{193}\textrm{Ir}$ isotope = $(1-0.3710)=0.6290\times 100=62.90\%$

Hence, the percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

8 0

3 years ago