Answer:
Empirical formula of 81.8 carbon and 18.2 hydrogen
Steps
- Find the empirical formula of a compound that has 81.8% of Carbon (C), 18.2% of Hydrogen (H).
- Divide by fractional component of each mole value: C=1.5354936431103, H=4.0709872862205Round to closest whole numbers: C=2, H=4
<h3> Combine to get the empirical formula: C2H4</h3>
the answer will there for be ironic
Answer:
the highest is "A" and the lower is "C"
The elements in the blocks of period 4-7 and group 3-12 in the periodic table are in the d-block and d-block elements are known as transition metals or transition elements.
Arsenic is a metalloid and it has four electron shells and five valence electrons.
the s and p orbital of Arsenic have 2 and 3 electrons respectively and which makes five valence electrons.
