Answer:
See explanation
Explanation:
The ionic radius of metal M decreases as the charge on the metal M increases. The ionic radius is generally defined as the distance between the nucleus and the outermost electron of the ion. Hence, ionic radius becomes much lesser as the magnitude of the positive charge increases.
It is obvious from the various formulae of metal chlorides in the question that the metal forms cations M^2+, M^3+ and M^4+ respectively. The order of decreasing ionic radius of the compounds is;
MX2 > MX3 > MX4
Well, radiation, in terms of physics, is the emission of electromagnetic waves
now, electromagnetic waves can take many different forms like visible light, radio waves, gamma radiation, ultraviolet light. Depending on its wavelength or frequency
thermal energy or heat generally takes the form of infrared light and all light is an form of electromagnetic wave
<em>≈ 4.10 g/cm³</em>
<em>Hi there ! </em>
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<em><u>Density formula</u></em>
<em>d = m/V</em>
<em>d = 6.13g/1.5cm³</em>
<em>d = 4.08(6) g/cm³ ≈ 4.10 g/cm³</em>
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<em>Good luck !</em>
If it is not an isotope then it has around 21 neutrons
Explanation:
The chemical reaction given in the question is as follows -
MnO₄⁻ (aq) + 8H⁺ (aq) + 5e⁻ → Mn²⁺ (aq) + 4H₂O (l)
NO₃⁻ (aq) + 4H⁺ (aq) + 3e⁻ → NO (g) + 2H₂O (l)
As we know , the value for reduction potential are -
Mn²⁺ = + 1.51 V
NO₃⁻ = +0.96 V
From , the data given above , the value of the reduction potential of NO₃⁻ is less than the reduction potential of Mn²⁺ .
Hence ,
NO₃⁻ can not oxidize Mn²⁺ .
