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leva [86]
4 years ago
6

3 | 5y - 7 | - 6 = 24

Mathematics
1 answer:
Gala2k [10]4 years ago
5 0
(3/5)*y-(7/(-6)) = 24 // - 24

(3/5)*y-(7/(-6))-24 = 0

(3/5)*y+7/6-24 = 0

3/5*y-137/6 = 0 // + 137/6

3/5*y = 137/6 // : 3/5

y = 137/6/3/5

y = 685/18

y = 685/18

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Working alone and at a constant rate, Machine A takes 3 hours to create a widget. Machine B, working alone and at a constant rat
PilotLPTM [1.2K]

Answer:

Time required by Machine B to create a widget = 4 hours

Step-by-step explanation:

Time taken by Machine A ( T_{A} ) = 3 hours

Time taken by Machine B ( T_{B} )= x hours

Time taken by both machines by working together = 12 hours

The time required to both machines by  working together to finish a task is given by the formula = \frac{T_{A} {T_{B} } }{T_{A} + T_{B} }

Put the values in above formula we get

⇒ T =  \frac{3 x}{3 + x}

⇒ 12 =  \frac{3 x}{3 + x}

⇒ 36 + 12 x = 3 x

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This is the time required by Machine B to create a widget.

8 0
3 years ago
If y varies directly with x and y = 6 when x = 2, what is the constant of variation, k? a. 12 c. 3 b. 2 d. 4 Please select the b
Vladimir79 [104]
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3 0
2 years ago
Simplify 18-2[x + (x - 5)].<br> O8-4x<br> 28 - 4x<br> 28 - 2x
densk [106]

Answer:

28-4x

Step-by-step explanation:

Step 1: Open most inner bracket and simplify

=18-2(x+x-5)

=18-2(2x-5)

Step 2: Expand brackets by multiplying 2 in and simplify

=18-2(2x)-2(-5)

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Therefore the answer is 28-4x

3 0
3 years ago
What is the measure of ZA?
ehidna [41]
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8 0
3 years ago
a barangay has 1000 individuals and its population doubles every 60 years. Give an exponential model for the barangay's populati
sdas [7]

Answer:

P(t) = 1000e^(0.01155)t

Step-by-step explanation:

Let the population of barangay be expressed according to the exponential formula;

P(t) = P0e^kt

P(t) is the population of the country after t years

P0 is the initial population

t is the time

If barangay has 1000 initially, this means that P0 = 1000

If the population doubles after 60years then;

at t = 60, P(t) = 2P0

Substitute into the formula

2P0 = P0e^k(60)

2 = e^60k

Apply ln to both sides

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ln2 = 60k

k = ln2/60

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Substitute k = 0.01155 and P0 into the expression

P(t) = 1000e^(0.01155)t

Hence an exponential model for barangay's population is

P(t) = 1000e^(0.01155)t

7 0
3 years ago
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