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2 years ago

Give the prime algebraic factorization: 15a2b = _____

Mathematics

1 answer:

Nookie1986 [14]2 years ago

7 0

Answer:

3a5a2b

Step-by-step explanation:

You can prime factorize 15: 3 x 5

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2x - 6 = 2 • (x - 3)
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2 years ago

X-2=3(x-4) what is the solution

Vladimir [108]

First distribute 3 to (x-4). that gives you 3x-12. Now your equation is x-2=3x-12. Now you subtract x from 3x. now you're equation is -2=2x-12. then add 12 to the left. You're final answer is 10.

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3 years ago

Read 2 more answers

When calculating a loanâ€™s effective interest rate, if the nominal rate is 8. 5%, what value of i do you plug into your equatio

natta225 [31]

The nominal rate to plug in will be 0.085.

Given to us, the nominal rate is 8.5%,

The value to plug into your equation,

The equation can be simple interest or compound interest in both cases the value of the nominal rate to the plugin will be the same.

Thus, the nominal rate is 8.5% can be written as

$\begin{aligned}Nominal rate&= 8.5\%\\&= \dfrac{8.5}{100} \\&= 0.085\end{aligned}$

Hence, the nominal rate to plug in will be 0.085.

To know more visit:

brainly.com/question/12522729

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2 years ago

1. Which ray is a bisector of BC BD BA BF 2. What is GH? 5 10 15 25 3. What is the value of

zhenek [66]

1. BD
2. 15
3. y=2
4. Angle(DBE)
5. 47

I hope this helps.
Next time try to post each question seperately

3 0

3 years ago

Marcos purchased a sail boat for $56,900. He anticipates each year the boat will decrease in value by 8.1% from the previous yea

Varvara68 [4.7K]

Answer: $56,900\left( 0.919\right)^x$

Step-by-step explanation:

Given

Marcos purchased a sailboat for $\$56,900$

Each year the boat will decrease in value by $8.1\%$

After 1 year it is

$\Rightarrow 56,900-56,900\times 0.081\\\Rightarrow 56,900\left( 1-0.081\right)\\$

after another year it becomes

$\Rightarrow 56,900\left( 1-0.081\right)-56,900\left( 1-0.081\right)\times 0.081\\\Rightarrow 56,900\left( 1-0.081\right)\cdot \left( 1-0.081\right)\\\Rightarrow 56,900\left( 1-0.081\right)^2$

After $x$ years it is

$\Rightarrow 56,900\left( 1-0.081\right)^x$

$\Rightarrow 56,900\left( 0.919\right)^x$

5 0

2 years ago