wheres the clouds?? i need a picture.
Answer:
d. 380g
Explanation:
The reaction of production of hydrogen from zinc and HCl is:
Zn + 2HCl → ZnCl₂ + H₂(g)
At STP (1atm of pressure and 273.15K), 112L are:
n = PV /RT
n = 1atm×112L / 0.082atmL/molK×273.15K
<em>n = 5.00 moles </em>
That means you need to produce 5.00 moles of hydrogen. Based on the reaction, 1 mole of Zn produce 1 mole of H₂(g), as yield of reaction is 85%:
5.00 moles H₂(g) ≡ 5.00 moles of Zn / 85% = <em>5.88 moles of Zn you need</em>
As molar mass of Zn is 65.38 g/mol:
5.88 moles Zn × (65.38g /mol) = 384 g of Zn ≡ <em>d. 380g</em>
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I hope it helps!
Answer: picture shows work for # 1,2,4,5,7
Explanation:
number 3: as the pressure in the volume decreases, the volume increases causing it to expand and eventually blow.
number 6: because the temperature and the amount of gas don’t change, these terms don’t appear in the equation. What Boyle’s law means is that the volume of a mass of gas is inversely proportional to its pressure. This linear relationship between pressure and volume means doubling the volume of a given mass of gas decreases its pressure by half.
hope this helps :))
Answer : The concentration of HI (g) at equilibrium is, 0.643 M
Explanation :
The given chemical reaction is:

Initial conc. 0.10 0.10 0.50
At eqm. (0.10-x) (0.10-x) (0.50+2x)
As we are given:

The expression for equilibrium constant is:
![K_c=\frac{[HI]^2}{[H_2][I_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5BI_2%5D%7D)
Now put all the given values in this expression, we get:

x = 0.0713 and x = 0.134
We are neglecting value of x = 0.134 because the equilibrium concentration can not be more than initial concentration.
Thus, we are taking value of x = 0.0713
The concentration of HI (g) at equilibrium = (0.50+2x) = [0.50+2(0.0713)] = 0.643 M
Thus, the concentration of HI (g) at equilibrium is, 0.643 M