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Butoxors [25]
3 years ago
5

Two identical ice hockey pucks, labeled A and B, are sliding toward each other at speed v. Which one of the following statements

is true concerning their momenta and kinetic energies?
a. p(A) = p(B) and KEA= KEB
b. pA= - pB and KEA= -KEB
c. pA= -pB and KEA= KEB
d. pa= pb and KEA =- KEB
Physics
1 answer:
ollegr [7]3 years ago
7 0

Answer:

C. p_{A} = -p_{B} and K_{A} = K_{B}.

Explanation:

The two hockey pucks travels in opposite sides with velocities of same magnitude, by definitions of linear momentum and translational kinetic energy:

Linear momentum

<em>Hockey puck A</em>

p_{A} = m\cdot v (1)

<em>Hockey puck B</em>

p_{B} = -m\cdot v (2)

p_{A} = -p_{B}

Translational kinetic energy

<em>Hockey puck A</em>

K_{A} = \frac{1}{2}\cdot m\cdot (v)^{2}

K_{A} = \frac{1}{2}\cdot m \cdot v^{2} (3)

<em>Hockey puck B</em>

K_{B} = \frac{1}{2}\cdot m\cdot (-v)^{2}

K_{B} = \frac{1}{2}\cdot m \cdot v^{2} (4)

K_{A} = K_{B}

Hence, the correct answer is C.

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How many neutrons does an atom of Dubnium have in its nucleus
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3 years ago
If someone looks far enough into space, they should be able to see the beginning of the universe true of false
kodGreya [7K]
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8 0
3 years ago
8. An airplane is flying at 200 m/s when it touches the ground at the airport. It has a constant negative acceleration, and slow
Temka [501]

Answer:

Explanation:

Given

Initial velocity u = 200m/s

Final velocity = 4m/s

Distance S = 4000m

Required

Acceleration

Substitute the given parameters into the formula

v² = u²+2as

4² = 200²+2a(4000)

16 = 40000+8000a

8000a = 16-40000

8000a = -39,984

a = - 39,984/8000

a = -4.998m/s²

Hence the acceleration is -4.998m/s²

8 0
3 years ago
The magnetic field at 8 cm distance from a long straight wire, carrying is 0.2x10^-5 T. How much is the electric current in the
FrozenT [24]

Answer:

The electric current in the wire is 0.8 A

Explanation:

We solve this problem by applying the formula of the magnetic field generated at a distance by a long and straight conductor wire that carries electric current, as follows:

B=\frac{2\pi*a }{u*I}

B= Magnetic field due to a straight and long wire that carries current

u= Free space permeability

I= Electrical current passing through the wire

a  = Perpendicular distance from the wire to the point where the magnetic field is located

Magnetic Field Calculation

We cleared (I) of the formula (1):

I=\frac{2\pi*a*B }{u} Formula(2)

B=0.2*10^{-5}  T = 0.2*10^{-5} \frac{weber}{m^{2} }

a  =8cm=0.08m

u=4*\pi *10^{-7} \frac{Weber}{A*m}

We replace the known information in the formula (2)

I=\frac{2\pi*0.08*0.2*10^{-5}  }{4\pi *10x^{-7} }

I=0.8 A

Answer: The electric current in the wire is 0.8 A

4 0
3 years ago
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