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sladkih [1.3K]
3 years ago
11

8. An airplane is flying at 200 m/s when it touches the ground at the airport. It has a constant negative acceleration, and slow

s
down to a speed of 4 m/s after it traveled a length of 4,000 meters. What was the acceleration?
Physics
1 answer:
Temka [501]3 years ago
8 0

Answer:

Explanation:

Given

Initial velocity u = 200m/s

Final velocity = 4m/s

Distance S = 4000m

Required

Acceleration

Substitute the given parameters into the formula

v² = u²+2as

4² = 200²+2a(4000)

16 = 40000+8000a

8000a = 16-40000

8000a = -39,984

a = - 39,984/8000

a = -4.998m/s²

Hence the acceleration is -4.998m/s²

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Help Please!!!
Sladkaya [172]

Answer:

1.16\cdot 10^{-7} N

Explanation:

The force of gravity between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is their separation

In this problem, we have

m1 = m2 = 1170 kg is the mass of each car

r = 28 m is their separation

Substituting,

F=(6.67\cdot 10^{-11} )\frac{(1170 kg)^2}{(28 m)^2}=1.16\cdot 10^{-7} N

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3 years ago
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Otrada [13]

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3 years ago
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4 years ago
What is the ultimate source of electromagnetic waves?
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Monochromatic light with wavelength 588 nm is incident on a slit with width 0.0351 mm. The distance from the slit to a screen is
Norma-Jean [14]

Answer:

Explanation:

A. Using

Sinစ= y/ L = 0.013/2.7= 0.00481

စ=0.28°

B.here we use

Alpha= πsinစa/lambda

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