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3 years ago

15

he velocity function is v(t)=t2−5t+6 for a particle moving along a line. Find the displacement and the distance traveled by the

particle during the time interval [−1,6].

1 answer:

antiseptic1488 [7]3 years ago

5 0

Answer:26.83

Step-by-step explanation:

We will be solving this question using integration. The question has been solved in the diagram

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Answer:

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Step-by-step explanation:

1. First, let's solve the system of equations; $-m - n = 5, m - n = -3$

Solve -m - n = 5 for m.

$-m -n = 5$
$-m-n+n=5+n$
$-m = n + 5$
$\frac{-m}{-1} = \frac{n+5}{-1}$
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Substitute -n - 5 for m in m - n = -3.

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$-n - 5 - n = -3$
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Substitute -1 for n in m = -n - 5.

$m = -n - 5$
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2. Okay, now that we know m = -4 and n = -1, let's solve for m^2 -n^2.

$m^2-n^2$
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