All categories

3 years ago

Steps involved in hydrometallurgy

1 answer:

5 0

Hi there

Steps are

Pretreatment

Reductive leaching

Precipitating of Ni

Precipitation of Co

Extraction of Mn^2+

Precipitating of Li

Hope this helped!

You might be interested in

At 1.00 atm and 0 ∘ C, a 5.04 L mixture of methane ( CH 4 ) and propane ( C 3 H 8 ) was burned, producing 15.0 g CO 2 . What was

diamong [38]

Answer : The mole fraction of methane and propane is, 0.742 and 0.26

Explanation :

First we have to calculate the moles of mixture by using ideal gas equation.

PV = nRT

where,

P = pressure of the mixture = 1.00 atm

V = Volume of the mixture = 5.04 L

T = Temperature of the mixture = $0^oC=[0+273]K=273K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles of mixture = ?

Putting values in above equation, we get:

$1.00atm\times 5.04L=n_{mix}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 273K\\n_{mix}=\frac{1.00\times 5.04}{0.0821\times 273}=0.225mol$

Let the number of moles of methane be 'x' moles and that of propane be 'y' moles

So, $x+y=0.225$ .....(1)

The chemical equation for the combustion of methane follows:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

By Stoichiometry of the reaction:

1 mole of methane produces 1 mole of carbon dioxide

So, 'x' moles of methane will produce = $\frac{1}{1}\times x=x$ moles of carbon dioxide

The chemical equation for the combustion of propane follows:

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

By Stoichiometry of the reaction:

1 mole of propane produces 3 mole of carbon dioxide

So, 'y' moles of propane will produce = $\frac{1}{1}\times y=y$ moles of carbon dioxide

Now we have to calculate the mass of carbon dioxide.

Total moles of carbon dioxide = (x + 3y)

Mass of carbon dioxide = (Total moles) × (Molar mass of carbon dioxide)

Molar mass of carbon dioxide = 44 g/mol

Mass of carbon dioxide = $(x+3y)\times 44$

As we are given:

Mass of carbon dioxide = 15.0 g

So, $44(x+3y)=15.0$ .....(2)

Putting value of 'x' from equation 1, in equation 2, we get:

$44(0.225-y+3y)=15.0\\\\0.225+2y=0.341\\\\y=0.058$

Evaluating value of 'x' from equation 1, we get:

$x+0.058=0.225\\x=0.167$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

For Methane:

$\chi_A=\frac{n_A}{n_A+n_B}$

Moles of methane = 0.167 moles

Total moles = 0.225

Putting values in above equation, we get:

$\chi_{(Methane)}=\frac{0.167}{0.225}=0.742$

For Propane:

Moles of propane = 0.058 moles

Total moles = 0.225

Putting values in above equation, we get:

$\chi_{(Propane)}=\frac{0.058}{0.225}=0.26$

Hence, the mole fraction of methane and propane is, 0.742 and 0.26

6 0

4 years ago

What are the 20 elements of periodic table

sergij07 [2.7K]

Answer:

H - Hydrogen

He - Helium

Li - Lithium

Be - Beryllium

B - Boron

C - Carbon

N - Nitrogen

O - Oxygen

F - Fluorine

Ne - Neon

Na - Sodium

Mg - Magnesium

Al - Aluminum

Si - Silicon

P - Phosphorus

S - Sulfur

Cl - Chlorine

Ar - Argon

K - Potassium

Ca - Calcium

3 0

3 years ago

How many moles of atoms are there in 8.0 g of Mg?

JulsSmile [24]

Answer:

0.33

Explanation:

1mol=24

x=8

=0.33

5 0

4 years ago

Read 2 more answers

what is the mass of a gold bar with the following dimensions" 30 cm X 10 cm X 10 cm if the density of gold is 19.3g/cm^3?

Lapatulllka [165]

Answer:

Volume of the bar=10 X 4 X 5=200 cm^3

Mass=200 X 19.3=3,860 grams

Mass=3.86 Kilograms

Explanation:

8 0

3 years ago

What would happen to a eukaryotic cell if its all mitochondria were destroyed

atroni [7]

Golgi complex would happen <span>to a eukaryotic cell if its all mitochondria were destroyed. Basically the cell will not be able to produce the ATP required for the cell to function properly. This can lead to cell death as well. I hope that this is the answer that has actually come to your great help.</span>

5 0

3 years ago

Steps involved in hydrometallurgy​

Steps involved in hydrometallurgy