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Pavlova-9 [17]
2 years ago
8

if 3.26 g of FeNO33 is dissolved in enough water to make exactly what is the molar concentration of nitrate ion g

Chemistry
1 answer:
Tanzania [10]2 years ago
5 0

Answer:

0.404M

Explanation:

...<em>To make exactly 100.0mL of solution...</em>

Molar concentration is defined as the amount of moles of a solute (In this case, nitrate ion, NO₃⁻) in 1 L of solution.

To solve this question we need to convert the mass of Fe(NO₃)₃ to moles. As 1 mole of Fe(NO₃)₃ contains 3 moles of nitrate ion we can find moles of nitrate ion in 100.0mL of solution, and we can solve the amount of moles per liter:

<em>Moles Fe(NO₃)₃ -Molar mass: 241.86g/mol-:</em>

3.26g * (1mol / 241.86g) =

0.01348 moles Fe(NO₃)₃ * (3 moles of NO₃⁻ / 1mole Fe(NO₃)₃) =

<em>0.0404 moles of NO₃⁻</em>

In 100mL = 0.1L, the molar concentration is:

0.0404 moles of NO₃⁻ / 0.100L =

<h3>0.404M</h3>
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Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:
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where z = atomic mass number

n = energy level

For hydrogen z = 1

Therefore, Energy for n = 1

E_{n} = 13.6 * 1^{2} / 1^{2} eV

     = -13.6 eV

for n = 2

E_{n} = 13.6 * 1^{2} / 2^{2} eV

     = -3.40 eV

for n = 3

 E_{n} = 13.6 * 1^{2} / 3^{2} eV

      = -1.51 eV

for n = 4

 E_{n} = 13.6 * 1^{2} / 4^{2} eV

      = -0.85 eV

for n = 5

 E_{n} = 13.6 * 1^{2} / 5^{2} eV

      = -0.544 eV

n = 2 to n = 4 (absorption)

ΔE = E4 - E2   = -0.85 - (-3.40) = 2.55 eV

n = 2 to n = 1 (emission)

ΔE =  E1 - E2  = -13.6 - (-3.40) = -10.2eV

The negative sign indicates that emission will take place.

n = 2 to n = 5 (absorption)

ΔE = E5 - E2 = -0.544 - (-3.40) = 2.856 eV

n = 4 to n = 3 (emission)

ΔE = E3 - E4 = -1.51 - (-0.85) = -0.66 eV

We know that

E = h * υ

Therefore, Energy is proportional to frequency.

So increasing the order of energy is

E4  < E1  < E3  <  E2

order of frequency is

d < a < c < b

For more information click on the link below:

brainly.com/question/17058029

# SPJ4

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