All categories

2 years ago

What is the definition of the molar mass of an element or compound?

Chemistry

1 answer:

VashaNatasha [74]2 years ago

8 0

Answer:

The molar mass is the mass of a given chemical element or chemical compound (g) divided by the amount of substance(mol) .

Explanation:

hope it may help you

mark as brainlist please

You might be interested in

Insulin is a protein that is used by the body to regulate both carbohydrate and fat metabolism. A bottle contains 375 mL of insu

Kitty [74]

Mass = Density × Volume
= 30.0 mg / mL × 375 mL
= 11250 mg
= 11.25 g

∴ the total mass of insulin in the bottle is 11.25 g (11250 mg)

4 0

2 years ago

HELP PLEASE

vodomira [7]

Answer:

4) how charged the object creating the field is and the distance between the two charged objects

3 0

2 years ago

If a sodium ion has 11 protons, 12 neutrons, and 11 electrons, what is the atomic mass of the atom?

iragen [17]

Answer:

Explanation:

we do not care about electrons, so 11 + 12 = 23

7 0

2 years ago

An aqueous antifreeze solution is 60.0% ethylene glycol (HOCH2CH2OH) by mass and has a density of 1.06 g/mL. Calculate the molal

galina1969 [7]

Answer:

[HOCH₂CH₂OH] = 24.1 m

Explanation:

Ethylene glycol → HOCH₂CH₂OH

60% by mass means that 60 g of ethylene glycol are contained in 100 g of solution.

Solution mass = Solute mass + Solvent mass

100 g = 60 g + Solvent mass

Solvent mass = 40 g

Molality are the moles of solute contained in 1kg of solvent.

We determine the moles of solute → 60 g . 1mol/62 g = 0.967 moles

We convert the mass of solvent from g to kg → 40 g . 1kg/1000 g = 0.04 kg

Molality → 0.967 mol / 0.04 kg = 24.1 m

4 0

3 years ago

Assuming the same temperature and pressure for each gas, how many milliliters of carbon dioxide are produced from 16.0 mL of CO?

Vlada [557]

Answer:

$V_{CO_2}=16.0mL$

Explanation:

Hello,

In this case, given that the same temperature and pressure is given for all the gases, we can notice that 16.0 mL are related with two moles of carbon monoxide by means of the Avogadro's law which allows us to understand the volume-moles relationship as a directly proportional relationship. In such a way, since in the chemical reaction:

$2CO(g)+O_2(g)\rightarrow 2CO_2(g)$

We notice two moles of carbon monoxide yield two moles of carbon dioxide, therefore we have the relationship:

$n_{CO}V_{CO}=n_{CO_2}V_{CO_2}$

Thus, solving for the yielded volume of carbon dioxide we obtain:

$V_{CO_2}=\frac{n_{CO}V_{CO}}{n_{CO_2}} =\frac{2mol*16.0mL}{2mol}\\ \\V_{CO_2}=16.0mL$

Best regards.

4 0

3 years ago