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Alecsey [184]
3 years ago
13

two sides of a triangle are equal in length. The length of the third side exceeds the length of one of the other sides by 3 cent

imeters. The perimeter of the triangle is 93 centimeters. Find the length of each side of the triangle.
Mathematics
1 answer:
AnnyKZ [126]3 years ago
6 0

Answer:

30, 30 and 33

Step-by-step explanation:

93-3=90\\90÷3=30\\#30, 30, 33

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Segment AB has endpoints at A(-7,2) and b(9,-6). Point P lies on AB such that AP:BP=3:1
bekas [8.4K]

The coordinates of the point P which divides the line segment AB made by the points A(-7,2) and B(9,-6) is  (x,y) = (5,-4)

<h3>What is the coordinate of the point which divides a line segment in a specified ratio?</h3>

Suppose that there is a line segment \overline{AB}such that a point P(x,y) lying on that line segment \overline{AB} divides the line segment  \overline{AB} in m:n, then, the coordinates of the point P is given by:

(x,y) = \left( \dfrac{mx_2 + nx_1}{m+n} , \dfrac{my_2 + ny_1}{m+n} \right)

where we have:

  • the coordinate of A is (x_1, y_1)
  • and the coordinate of B is (x_2, y_2)

We're given that:

  • Coordinate of A is (x_1, y_1) = (-7,2)
  • Coordinate of B is (x_2, y_2) = (9.-6)
  • The point P lies on AB such that AP:BP=3:1 (so m = 3, and n = 1)

Let the coordinate of P be (x,y), then we get the values of x and y as:

(x,y) = \left( \dfrac{mx_2 + nx_1}{m+n} , \dfrac{my_2 + ny_1}{m+n} \right)\\\\(x,y) = \left( \dfrac{3(9) + 1(-7)}{3+1} , \dfrac{3(-6) + 1(2)}{3+1} \right)\\\\(x,y) = \left( \dfrac{20}{4} , \dfrac{-16}{4} \right) = (5,-4)

Thus, the coordinates of the point P which divides the line segment AB made by the points A(-7,2) and B(9,-6) is  (x,y) = (5,-4)

Learn more about a point dividing a line segment in a ratio here:

brainly.com/question/14186383

#SPJ1

4 0
2 years ago
Suppose that c varies jointly with d and the square of g, and c = 30 when d = 15 and g = 2.
maksim [4K]

Answer:

d = \dfrac{3}{16}

Step-by-step explanation:

c varies jointly with d and the square of g

c\propto dg^2

c=kdg^2

where, k is constant of proportionality.

Put the given value c = 30 when d = 15 and g = 2 and find out k

30=k\cdot 15\cdot 2^2

k=\dfrac{1}{2}

c=\dfrac{1}{2}kg^2

If c = 6 and g = 8 then d = ?

6=\dfrac{1}{2}\cdot d\cdot 8^2

d=\dfrac{6\cdot 2}{8^2}

d=\dfrac{3}{16}

Hence, The value of d is \dfrac{3}{16}

5 0
3 years ago
A bank loaned out $22,500, part of it at the rate of 14% annual interest, and the rest at 2% annual interest. The total interest
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Answer:

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Step-by-step explanation:

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3 0
2 years ago
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