The length of q, to the nearest 10th of a centimeter is 7.6 cm.
Given in question,
In ΔOPQ,
o = 9.2 cm
p = 2.4 cm
∠Q = 37°
Cosine formula ⇒ cos θ = 
Putting the values in equation,
cos 37 = 
0.799 = 
0.799*44.16 = 90.4 - 
32.28 = 90.4 -
= 90.4 - 32.28
= 58.12
q = 7.6 cm (to nearest 10th)
Hence, length of q is 7.6 cm.
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We are given the equation:
DA - 2qA = B³
Taking 'A' common on the LHS
A(D - 2q) = B³
Dividing both sides by (D - 2q)
A = B³ / (D - 2q)
Answer:
Chang sent 17 messages, Alonzo sent 51 and Raina sent 26.
Step-by-step explanation:
You turn the word problem into an algebraic expression and solve
Algebra -> Polygons<span> -> SOLUTION: </span>Each exterior angle<span> is 100º </span>less than<span> its </span>interior angle<span> of ...</span>180<span>-x = </span>measure<span> of the corresponding </span>exterior angle<span> in degrees. </span>At each<span> vertex, there is an </span>interior angle<span> of </span>the polygon. ... The sum of the angles in those triangles (180+180<span>=360) is the same as the sum ... If a regular </span>polygon<span> has x sides, </span>then<span> the degree </span>measure<span>of </span>each exterior angle<span> is 360 divided by x.
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Could you rephrase that? Is it just 14 multiplied by 14?
