Answer:
In the given figure, There are two atoms -
- Sodium ( Na )
- Chlorine ( Cl )
sodium has one electron in valence shell and to get noble gas configuration ( stability ) it need to donate the outer most electron.
whereas,
chlorine has 7 electrons in valence shell and to get noble gas configuration ( stability ) it need to get one more electron.
in this condition Na ( sodium ) donates it's outermost electron to Cl ( chlorine ) and both became stable.
but now sodium has more number of protons than the electrons hence it get positive (+) charge and chlorine has more electrons than the protons hence it get negative (-) charge
so, they get stick to each other by strong electrostatic force acting on the charged atoms and forms a salt " NaCl " ( sodium chloride ) .
<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
Back titration is a titration done in reverse; instead of titrating the original sample, a known excess of standard reagent is added to the solution, and the excess is titrated.
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Answer:
there is no d electron that can be promoted via the absorption of visible light
Explanation:
One of the properties of transition elements is the possession of incompletely filled d orbitals. This property accounts for their unique colours.
The colours of transition metal compounds stem from d-d transition of electrons due to the presence of vacant d orbitals of appropriate energy to which electrons could be promoted.
For elements whose atoms have a d10 configuration, such vacant orbitals does not exist hence their compounds are not colored.
Sometimes, the colour of transition metal compounds stem from ligand to metal charge transfer(LMCT) for instance in KMnO4.
It is going to be <span>Molar Volume
</span><span>3H2 + N2 --> 2NH3
</span><span> 54.1L*22.4 L/mol H2 , you can find mol of H2, then mol of NH3, and then L of NH3</span>
