Answer : The volume of
required to neutralize is, 340 mL
Explanation :
To calculate the volume of base (NaOH), we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:

Hence, the volume of
required to neutralize is, 340 mL
Answer:
The anawer of this question is 0.024 m/h
Explanation:
Other explanations of the question are additional.
13.8 moles of carbon = 12 g/mol*13.8 or 165.6 grams
165.6 grams/ 2.26 g/mL = 73.27434 or 73.3 mL
I hope this helps!!!!