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artcher [175]
3 years ago
9

An acidic solution could have a pH of A) 14 B) 10 C) 3 D) 7

Chemistry
1 answer:
Alenkinab [10]3 years ago
8 0

Answer:

Option (C) 3

Explanation:

The pH scale is a scale that ranges from 0 to 14. The pH reading has various notifications. These notifications are as follow:

1. If the pH reads between 0 and 6, then the solution is acidic.

2. If the pH reads 7, then the solution is neutral.

3. If the pH reads between 8 and 14, then the solution is basic.

With the above information, option C is the correct answer to the question.

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If the solubility of a gas is 10.5 g/L at 525 kPa pressure, what is the solubility of the gas when the pressure is 225 kPa? Show
Talja [164]

Answer:

4.5 g/L.

Explanation:

  • To solve this problem, we must mention Henry's law.
  • Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.
  • It can be expressed as: P = KS,

P is the partial pressure of the gas above the solution.

K is the Henry's law constant,

S is the solubility of the gas.

  • At two different pressures, we have two different solubilities of the gas.

<em>∴ P₁S₂ = P₂S₁.</em>

P₁ = 525.0 kPa & S₁ = 10.5 g/L.

P₂ = 225.0 kPa & S₂ = ??? g/L.

∴ S₂ = P₂S₁/P₁ = (225.0 kPa)(10.5 g/L) / (525.0 kPa) = 4.5 g/L.

8 0
3 years ago
Write the balance chemical equation for propane.
Mars2501 [29]
It would be 3C + 4H2 -> C3H8
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A(n) _____ is the smallest unit of an element that still retains the chemical and physical properties of that element.
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A sample of a compound of xenon and fluorine contains molecules of a single type; XeFn, where n is a whole number. If 5.0 x 1020
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Answer:

4

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by N_0.

Also, it is the number of particles in exactly 12.000 g of isotope carbon 12.

Avogadro constant:-

N_a=6.023\times 10^{23}

Hence,

Mass of XeF_n = 131.293+ n18.998 g

So,

6.023\times 10^{23}  molecules have a mass of 131.293+ n18.998 g

Also,

1  molecules have a mass of \frac{(131.293+ n18.998)}{6.023\times 10^{23}} g

So,

5.0\times 10^{20}  molecules have a mass of \frac{(131.293+ n18.998)}{6.023\times 10^{23}}\times 5.0\times 10^{20} g

Also, given mass = 0.172 g

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\frac{(131.293+ n18.998)}{6.023\times 10^{23}}\times 5.0\times 10^{20}=0.172

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4 0
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