Answer: $5,203.71
<u>Step-by-step explanation:</u>
1.040742
<u>x 5 000</u>
5203.710 000
Answer: C
Step-by-step explanation: Hope this help :D
Answer:
15% markup
Step-by-step explanation:
5% markup would be $1. Since 20*5% or 20*.05=1
We can multiply it by 3 to find the percent for $3 markup. Which is 15% or 0.15
8
these extra words are added to pad my precise answer with additional words so there will be enough more words
Answer:
The earning rate is approximately 0.08.
Step-by-step explanation:
We can determine the yearly rate by means of compound interest, which is defined by:
(Eq. 1)
Where:
- Initial deposit, measured in US dollars.
- Earning rate, dimensionless.
- Earning periods, measured in years.
We proceed to clear the earning rate within:
![\frac{C(t)}{C_{o}} = (1+r)^{t}](https://tex.z-dn.net/?f=%5Cfrac%7BC%28t%29%7D%7BC_%7Bo%7D%7D%20%3D%20%281%2Br%29%5E%7Bt%7D)
![\log \frac{C(t)}{C_{o}} = t\cdot \log (1+r)](https://tex.z-dn.net/?f=%5Clog%20%5Cfrac%7BC%28t%29%7D%7BC_%7Bo%7D%7D%20%3D%20t%5Ccdot%20%5Clog%20%281%2Br%29)
![\frac{1}{t}\cdot \log \frac{C(t)}{C_{o}} = \log (1+r)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bt%7D%5Ccdot%20%5Clog%20%5Cfrac%7BC%28t%29%7D%7BC_%7Bo%7D%7D%20%3D%20%5Clog%20%281%2Br%29)
![\log \left(\frac{C(t)}{C_{o}} \right)^{\frac{1}{t} } = \log (1+r)](https://tex.z-dn.net/?f=%5Clog%20%5Cleft%28%5Cfrac%7BC%28t%29%7D%7BC_%7Bo%7D%7D%20%5Cright%29%5E%7B%5Cfrac%7B1%7D%7Bt%7D%20%7D%20%3D%20%5Clog%20%281%2Br%29)
![\left(\frac{C(t)}{C_{o}} \right)^{\frac{1}{t} } = 1+r](https://tex.z-dn.net/?f=%5Cleft%28%5Cfrac%7BC%28t%29%7D%7BC_%7Bo%7D%7D%20%5Cright%29%5E%7B%5Cfrac%7B1%7D%7Bt%7D%20%7D%20%3D%201%2Br)
![r = \left(\frac{C(t)}{C_{o}} \right)^{\frac{1}{t} }-1](https://tex.z-dn.net/?f=r%20%3D%20%5Cleft%28%5Cfrac%7BC%28t%29%7D%7BC_%7Bo%7D%7D%20%5Cright%29%5E%7B%5Cfrac%7B1%7D%7Bt%7D%20%7D-1)
If we know that
and
, then the earning rate is:
![r = 2^{\frac{1}{9} }-1](https://tex.z-dn.net/?f=r%20%3D%202%5E%7B%5Cfrac%7B1%7D%7B9%7D%20%7D-1)
![r \approx 0.08](https://tex.z-dn.net/?f=r%20%5Capprox%200.08)
The earning rate is approximately 0.08.