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steposvetlana [31]
3 years ago
12

Multiplication & Division

Chemistry
2 answers:
Tatiana [17]3 years ago
6 0

Answer:

0.008 ÷ 51.3 = 0.00015594541910331380.00015594541910331382Round 0.0001559454191033138 → 0.0002 (Sig Figs: 1)

8090 [49]3 years ago
3 0

Answer:

2 * 10^-4

Explanation:

I got it from a calculator and when I put it in, it showed that it was correct.

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3 Cu + 8HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O
Zepler [3.9K]

Answer:

A shape has 2 pairs of parallel sides and no right angles. What shape is it?

Trapezoid

Parallelogram

Square

RectangleA shape has 2 pairs of parallel sides and no right angles. What shape is it?

Trapezoid

Parallelogram

Square

Rectangle

Explanation:

A shape has 2 pairs of parallel sides and no right angles. What shape is it?

Trapezoid

Parallelogram

Square

Rectangle

7 0
2 years ago
Convert 2.17 x 10 -8 Mg into pg
viktelen [127]
This answer is 24 because 2.17 x 10 -8 is 24 so that would be your answer
4 0
3 years ago
How many grams of a stock solution that is 92.5 percent H2SO4 by mass would be needed to make 250 grams of a 35.0 percent by mas
IrinaVladis [17]

94.6 g.  You must use 94.6 g of 92.5 % H_2SO_4 to make 250 g of 35.0 % H_2SO_4.

We can use a version of the <em>dilution formula</em>

<em>m</em>_1<em>C</em>_1 = <em>m</em>_2<em>C</em>_2

where

<em>m</em> represents the mass and

<em>C</em> represents the percent concentrations

We can rearrange the formula to get

<em>m</em>_2= <em>m</em>_1 × (<em>C</em>_1/<em>C</em>_2)

<em>m</em>_1 = 250 g; <em>C</em>_1 = 35.0 %

<em>m</em>_2 = ?; _____<em>C</em>_2 = 92.5 %

∴ <em>m</em>_2 = 250 g × (35.0 %/92.5 %) = 94.6 g

4 0
3 years ago
Which of the following actions will lead to an increase in pressure?
MatroZZZ [7]
By decreasing n we can increase presure because decrease in n will shift equilibrium to either forward or reverse direction
3 0
3 years ago
The energy of a pendulum is recorded at different positions in the table below. Use the data in the table to determine the amoun
natta225 [31]

Answer:

36.55 J

Explanation:

PE = Potential energy

KE = Kinetic energy

TE = Total energy

The following data were obtained from the question:

Position >> PE >>>>> KE >>>>>> TE

1 >>>>>>>> 72.26 >> 27.74 >>>> 100

2 >>>>>>>> 63.45 >> x >>>>>>>> 100

3 >>>>>>>> 58.09 >> 41.91 >>>>> 100

The kinetic energy of the pendulum at position 2 can be obtained as follow:

From the table above, at position 2,

Potential energy (PE) = 63.45 J

Kinetic energy (KE) = unknown = x

Total energy (TE) = 100 J

TE = PE + KE

100 = 63.45 + x

Collect like terms

100 – 63.45 = x

x = 36.55 J

Thus, the kinetic energy of the pendulum at position 2 is 36.55 J.

7 0
2 years ago
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