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Varvara68 [4.7K]
2 years ago
7

EXTRA CREDIT

Chemistry
1 answer:
marin [14]2 years ago
5 0

Answer:

\huge\boxed{\sf 36\ H\ atoms}

Explanation:

<u>Molecular formula from Glucose:</u>

C₆H₁₂O₆

<u>3 moles of Glucose:</u>

3C₆H₁₂O₆

In 1 mole of Glucose, there are 12 hydrogen atoms.

<u>In 3 moles:</u>

= 12 × 3

= 36 H atoms

\rule[225]{225}{2}

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If you had 15 molecules of H2 and an unlimited supply of N2, how many
Masja [62]

Answer:

10 molecules of NH₃.

Explanation:

N₂ + 3H₂ --> 2NH₃

As the N₂ supply is unlimited, what we need to do to solve this problem is <u>convert molecules of H₂ into molecules of NH₃</u>. To do so we use the <em>stoichiometric coefficients</em> of the balanced reaction:

  • 15 molecules H₂ * \frac{2moleculesNH_3}{3moleculesH_2} = 10 molecules NH₃

10 NH₃ molecules could be prepared from 15 molecules of H₂ and unlimited N₂.  

8 0
3 years ago
Determine % yield if a student obtains 45 g of product in an experiment and the theoretical amount is determined to be 50 g. *
ycow [4]

Answer:

90%

Explanation:

Percentage yield = ?

Theoretical yield = 50g

Actual yield = 45g

To calculate the percentage yield of a compound, we'll have to use the formula of percentage yield which is the ratio between the actual yield to theoretical multiplied by 100

Percentage yield = (actual yield / theoretical yield) × 100

Percentage yield = (45 / 50) × 100

Percentage yield = 0.9 × 100

Percentage yield = 90%

The percentage yield of the substance is 90%

6 0
3 years ago
Enter your answer in the provided box. Calcium hydroxide may be used to neutralize (completely react with) aqueous hydrochloric
NNADVOKAT [17]

Answer:

49.95 g of HCl

Explanation:

Let's formulate the chemical equation involved in the process:

Ca(OH)2 + 2 HCl → CaCl2 + 2 H2O

This means that we need 1 mole of Calcium hydroxide to neutralize 2 moles of hydrochloric acid. From this, we calculate the quantity of HCl moles that would be neutralized by 0.685 moles of Ca(OH)2

1 mole Ca(OH)2 ---- 2 moles HCl

0.685 moles Ca(OH)2 ---- x = 1.37 moles HCl

Now that we know the quantity of HCl moles that would react, let's calculate the quantity of grams this moles represent:

1 mole of HCl ---- 36.46094 g

1.37 moles ------ x = 49.95 g of HCl

3 0
3 years ago
if I took two electrons (negatively charged particles) and tried to put them near each other, what would happen?
Crazy boy [7]
Two electrons that are of the same charge will repel each other
5 0
3 years ago
What will be produced at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2
natita [175]

Answer:

At the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

Explanation:

At cathode, reduction reaction takes place.

The dissociation of MgI2 in aqueous solution is Mg2+(aq) and 2I−(aq)

Here, the Iodine reduces to 2I−(aq) from state of 0 (MgI2) to state of -1 (2I−(aq))

Hence, at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

6 0
3 years ago
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