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sweet [91]
3 years ago
5

Which of the following is not true of Mendel's experiment?

Chemistry
1 answer:
Karolina [17]3 years ago
5 0

I believe it is B. Green pods are recessive.

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What happens in nuclear decay?
NARA [144]

Answer:

Nuclear decay occurs when the nucleus of an atom is unstable and spontaneously emits energy in the form of radiation. The result is that the nucleus changes into the nucleus of one or more other elements. These daughter nuclei have a lower mass and are more stable (lower in energy) than the parent nucleus...

5 0
3 years ago
A student needs to prepare 50.0 mL of a 1.30 M aqueous H2O2 solution. Calculate the volume of 5.0 M H2O2 stock solution that sho
lisov135 [29]

Answer:

13.0mL

Explanation:

So this is a classic M1V1=M2V2 problem, where M is molarity and V is volume and the subsequent numbers represent the two sets of condition (1 being before dilution and 2 being after dilution)

So M1 is going to be 5.0M because it is our initial molarity and V1 is what we are trying to find since we are trying to find how much of initial volume should be diluted.

M2 is 1.30M since it is what molarity is after dilution and M2 is what volume is after dilution which is 50mL.

So M1V1=M2V2 (becomes an algebra problem)

5*V1=1.30*50

V1= 13.0mL

Now this answer should make sense since to dilute something with large molarity to small you only need very few mL than the final volume because you add water to dilute it.

7 0
3 years ago
CHEM AGAIN
slavikrds [6]

Answer:-

182 Kg

Explanation:-

Molar mass of CO = 12 x 1 + 16 x 1 = 28 grams

Molar mass of CH3OH = 12 x 1 + 1 x 3 + 16 x 1 + 1 x 1

= 32 grams

The balanced equation for this reaction is

CO(g)+H2(g)—> CH3OH(g)

From the equation we see

1 CH3OH is produced from 1 CO

32 grams of CH3OH is produced from 28 grams of CO.

208 Kg of CH3OH is produced from (28 gram x 208 Kg) / (32 gram)

= 182 Kg of CO

4 0
3 years ago
What two variables are needed to calculate molarity?
ludmilkaskok [199]
B. Moles of solute, liters of solution
3 0
3 years ago
A mixture contains 0.5 mol He, 0.09 mol CO2, 0.75 mol O2 and 1.5 mol At. Which gas has the highest partial pressure ?
Volgvan

Answer:

  • <u><em>At.</em></u>

Explanation:

The <em>partial pressure</em> of a gas in a mixture is equal to the mole fraction of the gas multipplied by the total pressure.

The mole fraction of a component in a mixture is equal to the number of moles of the component divided by the total number of moles in the mixture.

In the mixture given there are:

  • 0.5 mol He,
  • 0.09 mol CO₂,
  • 0.75 mol O₂, and
  • 1.5 mol At.

Hence, the gas with greatest number of moles, and, consequetly, greatest mole fraction and<em> highest partial pressure</em> is<em> At</em>.

7 0
3 years ago
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