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Ivahew [28]
3 years ago
9

A balloon contains 0.218mol of gas and has volume of 4.8 L. If an additional 0.075 mil of gas is added to the ballon, what is th

e final volume and how many molecules of gas are in the cylinder?
Chemistry
1 answer:
wariber [46]3 years ago
8 0

Answer:

1. 6.45 L

2. 1.76 x 10²³ molecules

Explanation:

1. Avagadros law states that volume of gas at constant temperature and pressure is directly proportional to the amount / number of moles of that gas

we can use the following equation

v1/n1 = v2/n2

where v1 is volume and n1 is number of moles at first instance

and v2 is volume and n2 is number of moles at second instance

at the first instance - n1 = 0.218 mol

second instance - n2  = 0.218 mol + 0.075 mol  = 0.293 mol

substituting the values

4.8 L / 0.218 mol = v2 / 0.293 mol

v2 = 6.45 L

new volume is 6.45 L

2. 1 mol of any substance is made of 6.022 x 10²³ units. These units could be atoms making up elements or molecules making up a compound.

therefore if 1 mol consists of 6.022 x 10²³  molecules

then 0.293 mol consists of - 6.022 x 10²³ molecules/mol x 0.293 mol = 1.76 x 10²³ molecules

therefore there are 1.76 x 10²³ molecules now in the cylinder

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when two heavy hydrogens combine to for helium , it results in the formation of energy, and a neutron, along with the helium atom

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3 years ago
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Suppose NAD is unavailable because NADH cannot be oxidized due to a mutation in the NADH dehydrogenase (Complex I). If FAD could
Dovator [93]

Answer:

FAD substitution will produce 28 ATP instead of 36.

Explanation:

NAD and FAD are coenzymes involved in reversible oxidation and reduction reactions. These compounds are also known as electron carriers. However NADH produce 3 electrons in electron transport chain and FADH2 produce 2 electron beacuase it transfer the electrons to second complex in ETC.

Normal prduction of ATP from glucose;

2 cytoplasmic NADH formed in glycolysis         Each yields 2 ATP   +4

2 NADH formed in the oxidation of pyruvate Each yields 3 ATP         +6

2 FADH2 formed in the citric acid cycle         Each yields 2 ATP         +4

6 NADH formed in the citric acid cycle             Each yields 3 ATP         +18

2 ATP from glycolysis                                                                                   +2  

2 ATP from citric acid cycle                                                                          +2                            

                                                                    Net yield ATP +36

C6H12O6 + 6 CO2 + 36 ADP + 36 Pi ⇒6 CO2 + 6 H2O + 36 ATP

If we replace the NAD with FAD the total ATP production would be.

2 cytoplasmic FADH2 formed in glycolysis          Each yields 2 ATP            +4

2 FADH2 formed in the oxidation of pyruvate   Each yields 3 ATP    +4

2 FADH2 formed in the citric acid cycle            Each yields 2 ATP    +4

6 FADH2 formed in the citric acid cycle                  Each yields 2 ATP   +12

2 ATP from glycolysis                                                                                    

+2

2 ATP from citric acid cycle                                                                            +2

                                                                  <u>Net yield ATP +28</u>

C6H12O6 + 6 CO2 + 28ADP + 28 Pi ⇒6 CO2 + 6 H2O + 28 ATP

7 0
3 years ago
A sample of air is slowly passed through aqueous Sodium hydroxide and then over heater copper. Which gases are removed by this p
bagirrra123 [75]

Carbon dioxide and oxygen are removed from the air.

Explanation:

When air is passed through aqueous sodium hydroxide solution the carbon dioxide is removed from the air.

First the carbon dioxide will dissolve and react with water to form carbonic acid ( H₂CO₃) :

CO₂ + H₂O → H₂CO₃

The the carbonic acid will react with sodium hydroxide to form sodium carbonate (Na₂CO₃):

H₂CO₃ + 2 NaOH → Na₂CO₃ + 2 H₂O

After this by passing the air over heated cooper the oxygen is removed.

2 Cu + O₂ → 2 CuO

Learn more about:

neutralization reaction

brainly.com/question/2632201

#learnwithBrainly

7 0
3 years ago
If m = 45g and V = 15ml, what is D in g/ml?​
ch4aika [34]

Answer:

3 g/mL

Explanation:

We know that the density of an object can be measured by dividing its mass (g) to its volume (mL).

Formula

D=m/v

Given data:

Mass= 45 g

Volume= 15 mL

Now we will put the values in formula:

D=45 g/ 15 mL= 3 g/mL

6 0
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State Hund’s rule in your own words, and show its application in the orbital diagram of the nitrogen atom.
zmey [24]

Answer:

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Explanation:

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