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3 years ago

What happens in a Lewis acid-based reaction

Chemistry

2 answers:

AleksAgata [21]3 years ago

7 0

Answer:

When an acid accepts an electron pair from a base

Explanation:

Just did a test with this exact same question :)

Mkey [24]3 years ago

6 0

A Lewis acid-base reaction occurs when a base donates a pair of electrons to an acid. ... A Brønsted-Lowry acid such as HCl is an acid-base adduct according to the Lewis concept, and proton transfer occurs because a more stable acid-base adduct is formed.

Example: Water (H2O) has two nonbonding pairs of electrons, so it donates one pair to the carbocation. As a result, one bond is formed and shared between carbon and oxygen. Water acts as a Lewis base because it is the electron pair donor in this reaction.

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Which combinations form compounds?

Elina [12.6K]

Elements combine to form chemical compounds that are often divided into two categories. Metals often react with nonmetals to form ionic compounds. These compounds are composed of positive and negative ions formed by adding or subtracting electrons from neutral atoms and molecules.

7 0

3 years ago

___CH4 + ___O2 → ___CO2 + ___H2O When you burn natural gas in the laboratory, methane burns. What numbers fill in the blanks to

Hitman42 [59]

Answer:

The coefficient are 1,2,1,2 ( option B is correct)

Explanation:

Step 1: Data given

Methane = CH4

Burning methane = CH4 + O2

Step 2: The unbalanced equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

Step 3: Balancing the equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

On the left side we have 4x H (in CH4), on the right side we have 2x H (in H2O). To balance the amount of H, on both sides, we have to multiply H2O (on the right side by 2).

CH4(g) + O2(g) → CO2(g) + 2H2O(g)

On the left side we have 2x O (in O2), on the right side we have 4x O (2x in CO2 and 2x in 2H2O). To balance the amount of O on both sides, we have to multiply O2 (on the left side by 2).

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

The coefficient are 1,2,1,2 ( option B is correct)

3 0

3 years ago

Ammonia gas can be prepared by the reaction CaO ( s ) + 2 NH 4 Cl ( s ) ⟶ 2 NH 3 ( g ) + H 2 O ( g ) + CaCl 2 ( s ) In an experi

bogdanovich [222]

The given question is incomplete. The complete question is ;

Ammonia gas can be prepared by the following reaction:

$CaO(s)+2NH_4Cl(s)\rightarrow 2NH_3(g)+H_2O(g)+CaCl_2(s)$

In an experiment, 27.6 g of ammonia gas, $NH_3$ , is produced when it was predicted that 50.2 g of $NH_3$ would form.

What is the theoretical yield of $NH_3$ ? What is the actual yeild of $NH_3$ ? What is the percent yeild of $NH_3$ ?

Answer: a) 50.2 g

b) 27.6 g

c) 5.0 %

Explanation:

a) Theoretical yield is defined as the amount of the product that is possible in the reaction.

Theoretical yield of $NH_3$ = 50.2 g

b) Experimental or actual yield is defined as the amount of the product that is actually formed in the reaction.

Experimental yield of $NH_3$ = 27.6 g

c) Percentage yield is defined as the ratio of experimental yileld to the theoretical yield in terms of percentage.

${\text {percentage yield}}=\frac{\text {Experimental yield}}{\text {Theoretical yield}}\times 100\%$

${\text {percentage yield}}=\frac{27.6g}{50.2g}\times 100\%=55.0\%$

Hence percentage yield for the reaction is 55.0 %.

3 0

3 years ago

Two gases, helium and X, are released from one end of an evacuated long cylinder at the same time. If it takes the helium atoms

Greeley [361]

Answer:

The correct answer is HOF gas.

Explanation:

Based on the given information, the helium atoms effuses three times faster in comparison to the gas X.

The rate of effusion is determined by,

r is inversely proportional to 1/√M, here M is the molecular mass of the gas.

and r is inversely proportional to 1/t, here t is the time taken for effusion.

Thus, t is directly proportional to √M

The molecular mass of He is 4.

tHe = tX/3 (Here tx is the time taken for gas X)

The molecular mass of X is not known.

tX/tHe =√Mx/MHe

3 = √Mx/4

By squaring both the sides we get,

9 = Mx/4

Mx = 36

36 is the molecular mass of gas HOF, that is, (1+16+19 = 36). Hence, the gas X is 36.

4 0

3 years ago

Which of the following will decrease the percentage ionization of 1.0 M acetic acid, CH3CO2H(aq)?

arlik [135]

Answer: C. Adding concentrated HCL(aq)

Explanation:

HCl is an efficient acid that will increase the quantity of H+ in the solution and thus reduce the ionizing percentage of Ch3CO2H. The amount of ionization of the latter would be reduced by the addition of strong acid to a solution of weak acid.

5 0

3 years ago