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3 years ago

What is the molarity of NO−3 in 0.160M KNO3?

1 answer:

5 0

A solution of KNO3 consists of ions of potassium and nitrate. The ionic equation is expressed as:

KNO3 = K+ + NO3-

There is 1 is to 1 ratio between the substances. So, the molarity of NO3- in the solution is calculated as follows:

0.160 mol / L KNO3 ( 1 mol NO3- / 1 mol KNO3 ) = 0.160 M NO3-

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~ WILL MARK AS BRAINLIEST ~

Genrish500 [490]

Answer:

200 grams is the mass of 15% of the solution of lime that is formed by dissolving 30g of calcium hydroxide in water.

Explanation:

Mass of solution = M

Mass percentage of the solution of lime = 15%

Mass of lime or calcium hydroxide = m = 30 g

The Formula of mass percentage is given as :

$m/m\%=\frac{m}{M}\times 100$

On substituting the values in ab above formula :

$15\%=\frac{30 g}{M}\times 100$

$M=\frac{30 g}{15}\times 100=200 g$

200 grams is the mass of 15% of the solution of lime that is formed by dissolving 30g of calcium hydroxide in water.

7 0

3 years ago

What is the pH of the solution at the endpoint of a titration

Arada [10]

Answer:

The pH at the equivalence point is 7.0.

Explanation:

This is because the solution only contains water and a salt that is neutral.

Since neither H+ or OH-, molecules remain in the solution.

We can conclude that the equivalence point is 7.0.

5 0

3 years ago

Calculate the molar solubility of silver(i) bromate with ksp = 5. 5×10-5. also, convert the molar solubility to the solubility.

Sindrei [870]

The molar solubility is 7.4× $10^{-3}$ M and the solubility is 7.4× $10^{-3}$ g/L .

Calculation ,

The dissociation of silver bromide is given as ,

$AgBr$ → $Ag ^{+}$ + $Br^{-}$

- S S

Ksp = [ $Ag ^{+}$ ] [ $Br^{-}$ ] = [S] [ S ] = $S^{2}$

S = √ Ksp = √ 5. 5× $10^{-5}$ = 7.4× $10^{-3}$

The solubility =7.4× $10^{-3}$ g/L

The molar solubility is the solubility of one mole of the substance.

Since , one mole of $AgBr$ is dissociates and form one mole of each $Ag ^{+}$ and $Br^{-}$ ion . So, solubility is equal to molar solubility but unit is different.

Molar solubility = 7.4× $10^{-3}$ mol/L = 7.4× $10^{-3}$ M

To learn more about molar solubility ,

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7 0

1 year ago

_ Na3PO4 + _ HCl NaCl + _ H3PO4

tatiyna

Answer:

Na₃PO₄ + 3HCl —> 3NaCl + H₃PO₄

The coefficients are: 1, 3, 3, 1

Explanation:

_Na₃PO₄ + __HCl —> __NaCl + _H₃PO₄

The above equation can be balance as follow:

Na₃PO₄ + HCl —> NaCl + H₃PO₄

There are 3 atoms of Na on the left side and 1 atom on the right side. It can be balance by writing 3 before NaCl as shown below:

Na₃PO₄ + HCl —> 3NaCl + H₃PO₄

There are 3 atoms of Cl on the right side and 1 atom on the left side. It can be balance by writing 3 before HCl as shown below:

Na₃PO₄ + 3HCl —> 3NaCl + H₃PO₄

Now, the equation is balanced.

The coefficients are: 1, 3, 3, 1

8 0

3 years ago

What is a vocab word for newton's second law?

olga nikolaevna [1]

Answer:

proportional. having a constant ratio. Second law: A body of mass m subject to a net force F undergoes an acceleration a that has the same direction as the force and a magnitude that is directly proportional to the force and inversely proportional to the mass, i.e., unbalanced.

Explanation:

hope it's help

8 0

3 years ago

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