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Stells [14]
3 years ago
6

What is the molarity of NO−3 in 0.160M KNO3?

Chemistry
1 answer:
zubka84 [21]3 years ago
5 0
A solution of KNO3 consists of ions of potassium and nitrate. The ionic equation is expressed as:

KNO3 = K+ + NO3-

There is 1 is to 1 ratio between the substances. So, the molarity of NO3- in the solution is calculated as follows:

0.160 mol / L KNO3 ( 1 mol NO3- / 1 mol KNO3 ) = 0.160 M NO3-
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Answer: The volume of the sample after the reaction takes place is 29.25 L.

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The given reaction equation is as follows.

OF_{2}(g) + H_{2}O(g) \rightarrow O_{2}(g) + 2HF(g)

So, moles of product formed are calculated as follows.

\frac{3}{2} \times 0.17 mol \\= 0.255 mol

Hence, the given data is as follows.

n_{1} = 0.17 mol,      n_{2} = 0.255 mol

V_{1} = 19.5 L,         V_{2} = ?

As the temperature and pressure are constant. Hence, formula used to calculate the volume of sample after the reaction is as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}

Substitute the values into above formula as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{19.5 L}{0.17 mol} = \frac{V_{2}}{0.255 mol}\\V_{2} = \frac{19.5 L \times 0.255 mol}{0.17 mol}\\= \frac{4.9725}{0.17} L\\= 29.25 L

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