Answer:
50% chance or 1/2.
Explanation:
Let's denote the no freckles allele with f and the freckles allele with F since it is dominant over the no freckles trait.
One parent is homozygous recessive: ff
The other parent is heterozygous (So they have freckles): Ff
Let's do a Punnett Square to calculate the possibility of the offspring having freckles or not. (The Punnett Square may not be perfect)
<u> | F f</u>
f | Ff ff
f | Ff ff
Two of the offspring have Ff, meaning they will have freckles, and two of the offspring have ff, meaning they will not have freckles.
2 out of 4 don't have freckles, which means a 50% chance or 1/2.
In this experiment, researchers compared how fast the junco populations adapted.
<h3>What is the focus of the study?</h3>
This study focuses on the adaption process of Juncos (a specific bird population) in urban environments and how they behave in terms of stress and boldness behavior (interest in exploring unknown areas).
<h3>How did the study work?</h3>
In this study, scientists compared the behavior of a population of birds in an urban area with the behavior of another population of birds that lived in a novel urban area to determine the adaptation process of the second population.
Note: This question is incomplete because the information about the study is missing; here is the name of the possible study: Boldness behavior and stress physiology in a novel urban environment suggest rapid correlated evolutionary adaptation
Learn more about studies in: brainly.com/question/21212415
