Answer:
d) 2, 4-Dimethylpentane
Explanation:
2, 4-Dimethylpentane is the c_7 compound that gives 3 signals in the broadband proton decoupled ¹³C spectrum.
This compound is classified as an alkane and it's chemical formula is [(CH3C)2CH]2CH2. It is a hydrocarbon that has no odor. When it is combined with other gas compounds it gives high octane fuel.
A.
Explain: I think this….
Answer:
Exothermic Reactions.
Explanation:
Reactions that release energy are called exothermic reactions.
Whereas that absorb energy are called Endothermic reactions.
More energy is being released to the surroundings than was absorbed to initiate and maintain the reaction in case of exothermic reactions.
Burning of a candle is an exothermic reaction.
NH3 = water (it is actually a water soluble gas)
C6H14 = CCl4 (C6H14 won't mix with water at all)
Na2S = water (Na2S is a salt. Salts dissolve best in water)
Br2 = CCl4, but it will also dissolve in water.
Answer:
The correct answer is 1.194 J/g.ºC
Explanation:
The heat released by the material is absorbed by the water. We put a minus sign (-) for a released heat and a plus sign (+) for an absorbed heat.
We know the mass of the material (mass mat= 25.0 g) and the mass of water (mass H20= 100.0 g) and the specific heat capacity of water is known (Shw=4.18 J/g.ºC), so we can equal the heat released by the material and the heat absorbed by water y calculate the specific heat capacity of the material (Shm) as follows:
heat released by material = heat absorbed by water
-(mass material x Shm x ΔT)= mass water x Shw x ΔT
-(25.0 g x Shm x (24ºC - 80ºC)= 100.0 g x 4.18 J/g.ºC x (24ºC-20ºC)
25.0 g x Shm x (56ºC) = 100.0 g x 4.18 J/g.ºC x 4ºC
⇒Shm= (100.0 g x 4.18 J/g.ºC x 4ºC)/(25.0 g x 56ºC)
Shm= 1.194 J/g.ºC
