Answer:
NaCl has a smaller lattice energy compared to CaO
Explanation:
We have remember that lattice energy increases as the size of the ions in the ionic solid decreases. According to Oxford dictionary; lattice energy is "a measure of the energy contained in the crystal lattice of a compound, equal to the energy that would be released if the component ions were brought together from infinity."
We know that the larger the magnitude of charge on a cation the smaller in size the cation is and the size of anions increase from left to right in the periodic table. Hence Ca^2+<Na^+ and O^2- < Cl^-. Therefore the lattice energy of CaO is greater than that of NaCl.
I think this because they are getting much older and weaker so they’re bones tend to break down easily
Answer:
See below.
Explanation:
That is because of the .48.
85.48 is closer to 85 than 86.
<h3>
Answer:</h3>
8 alpha particles
4 beta particles
<h3>
Explanation:</h3>
<u>We are given;</u>
- Neptunium-237
- Thallium-205
- Neptunium-237 undergoes beta and alpha decay to form Thallium-205.
We are required to determine the number of beta and alpha particles produced to complete the decay series.
- We need to know that when a radioisotope emits an alpha particle the mass number reduces by 4 while the atomic number decreases by 2.
- When a beta particle is emitted the mass number of the radioisotope increases by 1 while the atomic number remains the same.
In this case;
Neptunium-237 has an atomic number 93, while,
Thallium-205 has an atomic number 81.
Therefore;
²³⁷₉₃Np → x⁴₂He + y⁰₋₁e + ²⁰⁵₈₁Ti
We can get x and y
237 = 4x + y(0) + 205
237-205 = 4x
4x = 32
x = 8
On the other hand;
93 = 2x + (-y) + 81
but x = 8
93 = 16 -y + 81
y = 4
Therefore, the complete decay equation is;
²³⁷₉₃Np → 8⁴₂He + 4⁰₋₁e + ²⁰⁵₈₁Ti
Thus, Neptunium-237 emits 8 alpha particles and 4 beta particles to become Thallium-205.
