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noname [10]
3 years ago
15

2

Mathematics
1 answer:
White raven [17]3 years ago
4 0

Answer: since 4mins->3math prob.

then 12/3=4 and 4x4=16

It will take him 16 minutes to solve 12 math problems

Step-by-step explanation:

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If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen
alexandr1967 [171]

The new equation after the expression equivalent to x from the first equation is substituted into the second equation is: 2(-4y-9)+5y=-6

Step-by-step explanation:

We will solve the initial steps for substitution method for finding the correct answer

Given equations are:

x+4y = -9\ \  \ \ Eqn1\\2x+5y=-6\ \ \ Eqn2

From equation one

x+4y = -9\\x+4y-4y = -9-4y\\x = -4y-9

Putting x = -4y-9 in equation 2

2(-4y-9)+5y=-6

Hence,

The new equation after the expression equivalent to x from the first equation is substituted into the second equation is: 2(-4y-9)+5y=-6

Keywords: Linear equations, variables

Learn more about linear equations at:

  • brainly.com/question/726990
  • brainly.com/question/725998

#LearnwithBrainly

6 0
3 years ago
What is the least common multiple of 10, 20, and 14?
lyudmila [28]

Answer:

The least common multiple would be 140.

Step-by-step explanation:

The least common multiple is known to be a multiple that is the lowest value that satisfies being a multiple with the other factors given.

The least common multiple was 140 as it was the lowest value that satisfied being a multiple of 14, 10, AND, 20,

14 * 10 = 140

20 * 7 = 140

10 * 14 = 140

7 0
3 years ago
Error Analysis: Pedro compares 7/33 and 2/11. He incorrectly says 7/33 < 2/11 because 4.71 < 5.50. Compare 7/33 and 2/11.
madreJ [45]
He divided the wrong way.  7/33 = .2121.....and 2/11 = .1818...., so actually 2/11 < 7/33
5 0
3 years ago
The nurse reported that Tricia's daughter had gained 4.2 pounds
tino4ka555 [31]
31.6-4.2=27.4 at last visit
6 0
3 years ago
If the area of a trapezoid is 28 m with a height of 14 m in with one of the base being 1 m to find the length of the second face
In-s [12.5K]
The area of a trapezoid is basically the average width times the altitude, or as a formula:
Area = h ·

b 1 + b 2
2


where
b1, b2 are the lengths of each base
h is the altitude (height)
Recall that the bases are the two parallel sides of the trapezoid. The altitude (or height) of a trapezoid is the perpendicular distance between the two bases.

In the applet above, click on "freeze dimensions". As you drag any vertex, you will see that the trapezoid redraws itself keeping the height and bases constant. Notice how the area does not change in the displayed formula. The area depends only on the height and base lengths, so as you can see, there are many trapezoids with a given set of dimensions which all have the same area.
4 0
3 years ago
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