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aalyn [17]
3 years ago
6

Tell me a secret and then i will mark you brainliest

Mathematics
2 answers:
grigory [225]3 years ago
8 0

Step-by-step explanation:

I just like hamburburs

Vinvika [58]3 years ago
3 0

Nono no well I like songs

Step-by-step explanation:lol

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A mechanical system is governed by the following differential equation what is the homogeneous solution
Anika [276]

The ODE has characteristic equation

r^2+6r+9=(r+3)^2=0

with roots r=-3, and hence the characteristic solution

y_c=C_1e^{-3t}+C_2te^{-3t}

For the particular solution, assume an ansatz of y_p=ae^{-t}, with derivatives

\dfrac{\mathrm dy_p}{\mathrm dt}=-ae^{-t}

\dfrac{\mathrm d^2y_p}{\mathrm dt^2}=ae^{-t}

Substituting these into the ODE gives

ae^{-t}-6ae^{-t}+9ae^{-t}=4ae^{-t}=4e^{-t}\implies a=1

so that the particular solution is

\boxed{y(t)=C_1e^{-3t}+C_2te^{-3t}+e^{-t}}

7 0
3 years ago
Hopefully this is enough for the answer
Tomtit [17]
It is the third one.
6 0
3 years ago
Which expression is equivalent 2(5)^4
DiKsa [7]
1,250 because you have to multiply 5 by 5 four times which is 625 and 625 multiplied by 2 is 1250.
8 0
3 years ago
What is the volume of the cylinder?
jeka57 [31]

Radius = Diameter ÷ 2

Radius = 10 ÷ 2 = 5

.

Volume = πr²h

Volume = π(5)² (20) = 500π cm³

.

Answer: 500π cm³

8 0
4 years ago
Read 2 more answers
US consumers are increasingly using debit cards as a substitute for cash and checks. From a sample of 100 consumers, the average
scoray [572]

Answer:

A. Margin of error = 128.79

B. The 99% confidence interval for the population mean is (7661.21, 7918.79).

Step-by-step explanation:

We have to calculate a 99% confidence interval for the mean.

The population standard deviation is know and is σ=500.

The sample mean is M=7790.

The sample size is N=100.

As σ is known, the standard error of the mean (σM) is calculated as:

\sigma_M=\dfrac{\sigma}{\sqrt{N}}=\dfrac{500}{\sqrt{100}}=\dfrac{500}{10}=50

The z-value for a 99% confidence interval is z=2.576.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=2.576 \cdot 50=128.79

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 7790-128.79=7661.21\\\\UL=M+t \cdot s_M = 7790+128.79=7918.79

The 99% confidence interval for the population mean is (7661.21, 7918.79).

8 0
3 years ago
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