Answer:
Computer, Microprocessor, Cell Phone, WWW, iPhone
Explanation:
i just did it and got it correct
Answer:
39.78 Kg
Explanation:
Data Given;
Density = 1.53 g/cm³
Mass = <u>??</u>
Volume = 26.0 L = 26000 cm³
Formula Used;
The measure of mass per unit volume is called as density. It is a physical property of a substance and tells how tightly the particles are packed. Mathematically;
Density = Mass ÷ Volume
Solving for Mass,
Mass = Volume × Density
Putting values,
Mass = 26000 cm³ × 1.53 g.mL⁻¹
Mass = 39780 g or 39.78 Kg
Answer:
THE PERCENT ERROR IS 5.55 %
Explanation:
To calculate the percent error, we use the formula:
Percent error = Found value - accepted value / accepted value * 100
Found value = 2.85 g/cm3
Accepted value = 2.70 g/cm3
Solving for the percent error, we have:
Percent error = 2.85 g/cm3 - 2.70 g/cm3 / 2.70 g/cm3 * 100
Percent error = 0.15 / 2.70 * 100
Percent error = 0.05555 * 100
Percent error = 5.55 %
In conclusion, the percent error is 5.55 %
Explanation:
As the given chemical reaction equation is as follows.
![2Cl_{2}(g) + 7O_{2}(g) + 130 kcal \rightarrow 2Cl_{2}O_{7}(g)](https://tex.z-dn.net/?f=2Cl_%7B2%7D%28g%29%20%2B%207O_%7B2%7D%28g%29%20%2B%20130%20kcal%20%5Crightarrow%202Cl_%7B2%7DO_%7B7%7D%28g%29)
Also, it is given that for 2 moles the energy required is 130 kcal. This means that energy required for 1 mole is calculated as follows.
1 mole = ![\frac{130 kcal}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B130%20kcal%7D%7B2%7D)
= 65 kcal
Hence, energy required for 7 moles will be calculated as follows.
Energy required = ![7 \times 65 kcal](https://tex.z-dn.net/?f=7%20%5Ctimes%2065%20kcal)
= 455 kcal
Thus, we can conclude that energy required to produce 7.00 mol
on the basis of given reaction is 455 kcal.