A sample of calcium oxide (CaO) has a mass of 2.80 g. The molar mass of CaO is 56.08 g/mol. How many moles of CaO does this samp
2 answers:
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Answer:
Work done in this process = 4053 J
Explanation:
Mass of the gas = 0.092 kg
Pressure is constant = 1 atm = 101325 pa
Initial temperature = 200 K
Final temperature = 200 - 85 = 115 K
Gas constant for nitrogen = 297
When pressure of a gas is constant, volume of the gas is directly proportional to its temperature.
⇒ V ∝ T
⇒ =
------------ ( 1 )
From ideal gas equation
= m R
------ (2)
⇒ 101325 × = 0.092 × 297 × 200
⇒ = 0.054
This is the volume at initial condition.
From equation 1
⇒ =
⇒ = 0.094
This is the volume at final condition.
Thus the work done is given by W = P [ -
]
⇒ W = 101325 × [ 0.094 - 0.054]
⇒ W = 4053 J
This is the work done in that process.