Substitution method is used to solve the linear system of equations for one or more variables.
Consider the first equation y = 3x + 3 -----(1)
In equation (1) plug in y=x-1, we get
x -1 = 3x + 3
Add -3x on both side , we get
x-3x -1 = 3x-3x +3
-2x-1=0 + 3
Now add +1 on both sides, we get
-2x-1+1= 3+1
-2x + 0 =4
Now divide both side by -2
-2x/-2= 4/-2
X= -2
Now put x=-2 in the the second equation,
y=x-1
y=(-2)-1
y=-3
Solution(-2,-3)
Answer:
⅘×⅛ = 1/10
Step-by-step explanation:
Answer:
A. because 3.7 ×2 is 7.4. so the full answer would be 7.4 ×10^4
9514 1404 393
Answer:
(x +3)² +(y -4)² = 145
Step-by-step explanation:
The center of the circle is the midpoint of the given segment PQ. If we call that point A, then ...
A = (P +Q)/2
A = ((-12, -4) +(6, 12))/2 = (-12+6, -4+12)/2 = (-6, 8)/2
A = (-3, 4)
The equation of the circle for some radius r is ...
(x -(-3))² +(y -4)² = r² . . . . . . where (-3, 4) is the center of the circle
The value of r² can be found by substituting either of the points on the circle. If we use Q, then we have ...
(6 +3)² +(12 -4)² = r² = 9² +8²
r² = 81 +64 = 145
Then the equation of the circle is ...
(x +3)² +(y -4)² = 145