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Vladimir79 [104]
3 years ago
6

The theater director offered every member of the drama one vote for which play they preferred to perform. The director found tha

t 3 5 % 35% voted for The Oddems Family, that 5 7 % 57% voted for Thirteenth Night, and that 8 % 8% did not vote. In this group, are the events "Oddems Family" and "Thirteenth Night" mutually exclusive?
Chemistry
2 answers:
frez [133]3 years ago
4 0

Answer:

Yes, In this group the events "Oddems Family" and "Thirteenth Night" are mutually exclusive.

Explanation:

Two events are called mutually exclusive if the intersection of these events is null set or Ф.

The director found that 35% voted for The Oddems Family, that 57% voted for Thirteenth Night, and that 8% did not vote.

One person can vote for only one drama, so the number of persons who vote for "Oddems Family" and "Thirteenth Night" both are 0.

Since the intersection of "Oddems Family" and "Thirteenth Night" is null set, therefore the group the events "Oddems Family" and "Thirteenth Night" are mutually exclusive.

irakobra [83]3 years ago
3 0
<h2>ANSWER:</h2>

Yes, in this group both events "Oddems Family" and "Thirteenth Night" are mutually exclusive.

<h3>Explanation:</h3>

Mutually exclusive is an statistical term which means the probability of occurrence of two separate event at the same time is zero. It means two events can not be occurred simultaneously.

For example, if we roll the deck ant the probability of coming 1 and 6 at the same time is zero and both events do not depends upon each others occurrence.

Hence only one drama can run in theater at one time. So they are mutually exclusive events.

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3 0
3 years ago
A solution of phosphoric acid was made by dissolving 10.8 g of H3PO4 in 133.00 mL of water. The resulting volume was 137 mL. Cal
Nesterboy [21]

Answer:

Density is: 1.05 g/ml

Mole fraction solute: 0.015

Mole fraction solvent:  0.095

Molarity: 0.80 M

Molality: 0.82 m

Explanation:

A typical excersise of solution.

It is more confortable to make a table for this.

                |   masss  |  volume  |  mol

solute       |                |                |          

solvent     |                |                |  

solution    |                |                |

Let's complete, what we have.

                 |   masss  |  volume  |  mol

solute       |  10.8g     |                |          

solvent     |                |  133 mL   |  

solution    |                |  137 mL    |

We can first, know how many moles are 10.8 g

Molar Mass H3PO4 = 97.99 g/mol

Mass / Molar mass = mol

10.8 g / 97.99 g/m = 0.110 mol

Density of water is 1 g/ml (it is a very knowly value)

From this data, we can know water mass, solvent.

Density = mass / volume

1 g/ml = mass / 133 mL

Mass = 133 g

We can also have the moles, by the molar mass of water 18 g/m

133 g / 18 g/m = 7.39 mol

                 |   masss  |  volume  |  mol

solute       |   10.8g     |                |   0.110 mol      

solvent     |   133g      |  133 mL   |  7.39 mol

solution    |   143.8g   |  137 mL   | 7.50 mol

Mass of solution will be solute mass + solvent mass

Moles of solution will be solute moles + solvent moles

Now we can calculate everything.

Molarity means mol of solute in 1 L of solution. (mol/L)

We have to convert 137 mL in L (/1000)

0.137L so → 0.110 m / 0.137L = 0.80 M

Molality means mol of solute in 1kg of solvent.

We have to convert 133g in kg (/1000)

0.133 kg so → 0.110 m/0.133 kg = 0.82 m

Density is mass / volume

Solution density will be solution mass / solution volume

143.8 g/137 mL = 1.05 g/m

Molar fraction is : solute moles / total moles  or  solvent moles/total moles.

You can also (x 100%) to have a percent of them.

Remember sum of molar fraction = 1

Molar fraction of solute = 0.110 mol / 7.50mol = 0.015

Molar fraction of solvent = 7.39 mol / 7.50 mol = 0.985

5 0
3 years ago
Which of the following provides the best analogy for an electron in an atomic orbital
Igoryamba

Answer:

a

Explanation:

the answer is a i'm pretty sure it might be wrong tho i'm sorry

5 0
3 years ago
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