Molar mass
H2S = 34.0 g/mol
O2 = 31.99 g/mol
S8 = 256.52 g/mol
Identifying excess reagent and the limiting of the reaction :
8 H2S(g) + 4 O2(g) = S8(I) + 8 H2O(g)
8 x 34 g H2S --------> 256. 52 g S8
35.0 g ----------------> ??
35.0 x 256.52 / 8 x 34 =
8978.2 / 272 => 33.00 g of S8
H2S is the limiting reactant
---------------------------------------------
4 x 31.99 g O2 --------------- 256.52 g S8
40.0 g O2 --------------------- ??
40.0 x 256.52 / 4 x 31.99 =
10260.8 / 127.96 = 80.16 g of S8
O2 is the excess reagent is the excess <span>reagent
</span>
------------------------------------------------------------
H2S is the limiting reactant, one that is fully consumed, it is he who determines the mass of S8 produced
33.0 g ----------- 100%
?? g ------------- 95 %
95 x 33.00 / 100 => 31.35 g
hope this helps!
Answer:
The value of the gas equilibrium constant Kp is 18.3
Explanation:
Step 1: Data given
Kp= Kc(RT)^Δn
Temperature = 298 K
Kc = 18.3
Step 2: The balanced equation
C₄(s) + 4 O₂(g) ⇌ 4 CO₂(g)
Step 3: Calculate Kp
Kp= Kc(RT)^Δn
⇒with Kp = the gas equilibrium constant = TO BE DETERMINED
⇒with Kc = the equilibrium constant = 18.3
⇒R = the gas constant = 0.08206 L* atm/mol*K
⇒T = the temperature = 298 K
⇒Δn = mol gas phase product – mol gas phase reactant = 4-4 =0
Kp = 18.3 * (0.08206*298)^0
Kp = 18.3 * 1
Kp = 18.3
The value of the gas equilibrium constant Kp is 18.3
Answer:
CO
Explanation:
Henry's law constant reflects the solubility of a gas in water. The larger the kH, the more soluble is the gas. There is a rule that states that "like dissolves like", meaning polar is soluble in polar and nonpolar is soluble in nonpolar. Since water is polar, we have to consider the nature of these gases.
<em>Xe</em> nonpolar
<em>Cl₂</em> nonpolar
<em>CO</em> polar
<em>CO₂</em> nonpolar
<em>CH₃CH₃</em> nonpolar
CO is the only polar gas, so it has the largest kH.
The other dude is rude wrong
The correct answer is Dmitri Mendeleev
Vas happenin!!
1 amu is the correct answer
Hope this helps
-Zayn Malik
