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Maslowich
3 years ago
6

Large crystals are made from the slow cooling of magma. a. True b. False

Chemistry
2 answers:
Andre45 [30]3 years ago
6 0
Slow cooling of intrusive igneous rocks form small crystals, while rapid cooling of extrusive igneous rock forms large extrusive crystals.
Step2247 [10]3 years ago
5 0
I would have to say the answer is a. True.
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20 POINTS!<br> I would like to know what the quantum theory is in detail, thanks!
Ainat [17]
Technically, "quantum theory" is actually just the theory associated with quantum mechanics, ie; the theory of any objects isolated from their surroundings but, because it is very difficult to isolate large objects from their environments, it essentially becomes a theory of the microscopic world of atoms and sub-atomic particles.
5 0
3 years ago
Calculate the number of atoms of bromine in 1.37 g of bromine. Give your answer in scientific notation. Enter your answer in the
steposvetlana [31]

<u>Answer:</u> The number of atoms of bromine present in given number of mass is 1.03\times 10^{22}

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of bromine = 1.37 g

Molar mass of bromine = 79.904 g/mol

Putting values in above equation, we get:

\text{Moles of bromine}=\frac{1.37g}{79.904g/mol}=0.0171mol

According to mole concept:

1 mole of an element contains 6.022\times 10^{23} number of atoms.

So, 0.0171 moles of bromine will contain = 0.0171\times 6.022\times 10^{23}=1.03\times 10^{22} number of bromine atoms.

Hence, the number of atoms of bromine present in given number of mass is 1.03\times 10^{22}

4 0
3 years ago
Two gases X and Y are found in the atmosphere in only trace amounts because they decompose quickly. When exposed to ultraviolet
igomit [66]

Answer:

1. Yes

2. After 68.1 mins, pX < pY.

Explanation:

Assuming the total gas pressure is 1 atm, let the partial pressure of Y be y, partial pressure of X will be 0.25y + y = 1.25y

1.25y + y = 1atm

2.25y = 1 atm

y = 1 atm / 2.25 = 0.44 atm

Then partial pressure of X = 0.56 atm

The partial pressure of a gas in a mixture of gases is directly proportional to the mole fraction of the gas.

Therefore the mole fraction of X and Y is 0.56 and 0.44 respectively.

The partial pressures of X and Y becomes half of their original values at 1.25 h = 85 min and Y at 150 min respectively.

The partial pressure after some time can be calculated from the half-life equation :

m = m⁰ *  1/2ⁿ

Where m = the remaining mass, m⁰ = initial mass, and n is number of half-lives undergone.

Let partial pressures represent the mass, and n for X and Y be a and b respectively:

pX  = 0.56/2ᵃ

pY = 0.44/2ᵇ

We then determine when Partial pressure of X, pX = Partial pressure of Y, pY

0.56/2ᵃ = 0.44/2ᵇ

2ᵃ/2ᵇ = 0.56/0.44

2ᵃ/2ᵇ = 1.27

2ᵃ⁻ᵇ = 2⁰°³⁴⁵

a - b = 0.345

Let this time be t, therefore,

For X; t = 85a and For Y: t = 150b

85a = 150b

then, a = 1.76b

1.76b - b = 0.345

0.760b = 0.345

b = 0.454 and,

a = 0.345 + 0.454 = 0.799

So,  X goes through 0.779 half-lives while Y goes through 0.454 half-lives Then, the time for both X and Y to have the same amount is:

t = 150 * 0.454 = 68.1 min

After 68.1 mins, pX < pY.

5 0
3 years ago
Consider the reaction 2Al(OH)3(s)→Al2O3(s)+3H2O(l) with enthalpy of reaction ΔHrxn∘=21.0kJ/mol What is the enthalpy of formation
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