Answer:
The number of seniors who scored above 96% is 1.
Step-by-step explanation:
Consider the provided information.
Two percent of all seniors in a class of 50 have scored above 96% on an ext exam.
Now we need to find the number of seniors who scored above 96%
For this we need to find the two percent of 50.
2% of 50 can be calculated as:
![\frac{2}{100}\times50](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B100%7D%5Ctimes50)
![\frac{100}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B100%7D%7B100%7D)
![1](https://tex.z-dn.net/?f=1)
Hence, the number of seniors who scored above 96% is 1.
I'm pretty sure it would be y=2x+9
According to the graph, the value of the constant in the equation below is 80 and is denoted as option D.
What is a Graph?
This is defined as a pictorial representation of data or variables in an organized manner.
From the equation: Height = constant/width
We can pick any point(4,20) on the graph.
20 = c/ 4
c = 20 × 4 = 80
Read more about Graph here brainly.com/question/19040584
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302.1 is the answer to the problem.
Answer:
55/2574 ≈ 2.18%
Step-by-step explanation:
There are a total of 13 people on the council.
The probability that the first person is a Democrat is 8/13.
The probability that the second person is a Democrat is 7/12.
The probability that the third person is a Republican is 5/11.
The probability that the fourth person is a Republican is 4/10.
The probability that the fifth person is a Republican is 3/9.
The total probability is:
P = (8/13) (7/12) (5/11) (4/10) (3/9)
P = 56/2574
P ≈ 0.0218
There is a 2.18% probability of selecting two Democrats and three Republicans.