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2 years ago

EASY POINTS FOR YALL

Mathematics

2 answers:

hjlf2 years ago

7 0

Answer:

I would say the answer is A

olga55 [171]2 years ago

5 0

Answer:

Step-by-step explanation:

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Answer:

how do you find the circumference of a circle??

C=2πr

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Let Y be a random variable with a density function given by

Neporo4naja [7]

From the given density function we find the distribution function,

$F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y$

(a)

$F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)$

$\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1$

$\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}$

(b)

$F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y$

$\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2$

$\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}$

(c)

$F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})$

$\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3$

$\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}$

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3 years ago

Use the diagram of the right triangle above and round your answer to the nearest hundredth. If measure B= 60 degrees and a = 10

Tamiku [17]

I need you to post a diagram.
However, you are describing a 30 60 90 triangle and here is a good page to learn about those: http://www.1728.org/trig2.htm

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Draw diagram to rerpresent the mixed number 3 2/3. How can u write this as a single fraction greater than one

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11/3 draw whatever u want

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3 years ago

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Help me pleaseeeeeeeeeeeeee

gavmur [86]

Answer:

68/35 hope this helps

Step-by-step explanation:

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