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coldgirl [10]
3 years ago
13

In a factory that makes bolts, 20% of the bolts being made by a certain machine are defective. The factory owner wants to determ

ine the probability that two bolts in a row will be defective. He decides to use random numbers as a simulation tool. The following list shows 100 two-digit numbers that were randomly generated to represent two bolts in a row. If he uses the digits 0 and 1 to represent defective bolts, how many times were two bolts in a row defective?
0
33
3
18
Mathematics
2 answers:
Alla [95]3 years ago
8 0

Answer:

18

Step-by-step explanation:

cause the 18 would be 20% and step by step equations

ikadub [295]3 years ago
5 0

Answer:

the answer is 3

Step-by-step explanation:

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Hose is 32 feet long 32 feet long it needs to be cut into pieces equaling 5’3” How many whole pieces can be cut into how many wh
luda_lava [24]

Answer:

6

Step-by-step explanation:

Question tests the ability to get quotient

Here, 32 ft is divided by 5’3”

Normally, ft is denoted by ' while inches is denoted by ". So we divide 32 ft by 5ft and 3 inches

First, we convert dimensions into similar units. To convert 5’3” to ft, we divide 3” by 12 hence 3÷12=0.25'

The total is now 5.25'

Now

32'÷5.25'=6.1538461538461

This means, we shall obtain 6 whole pieces with some remainder. Since the question needs the whole pieces only, then the answer is 6

3 0
3 years ago
Plz help................
Paul [167]
The answer is a^{2} +2a
3 0
3 years ago
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I don’t think I wanna do this
Vedmedyk [2.9K]
$89.10 is the best guess.
7 0
3 years ago
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A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat
Ivanshal [37]

We are told that a population of insects grows exponentially and we are given a table of data about insect population growth. We are asked to find population of insects at the end of week 11.        

The initial insect population is 20 and at the end of 1st week population increases to 30.

Let us find growth percentage of insect  population,

\text{Growth percentage}=\frac{\text{Difference}}{Actual} \cdot100

\text{Growth percentage}=\frac{\text{30-20}}{20} \cdot100

\text{Growth percentage}=\frac{\text{10}}{20} \cdot100

\text{Growth percentage}=0.5 \cdot100=50

We can see that insect population is growing at rate of 50% per week.

Now let us write an exponential function for our population.

P(w)=20(1+0.50)^{w}, where P(w) represents population at the end of w weeks.

Let us substitute w=11 in our function to find insect population at the end of 11 weeks.

P(11)=20(1+0.50)^{11}

P(11)=20(1.50)^{11}

P(11)=20\cdot 86.49755859375

P(11)=1729.951171875\approx 1730

Therefore, population of insects at the end of 11th week will be 1730.  



7 0
4 years ago
Identify the exponential function as a growth or decay function.
marusya05 [52]

Answer:

A

Step-by-step explanation:

A. growth

7 0
3 years ago
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