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Phoenix [80]
3 years ago
5

Find the slope.....​

Mathematics
1 answer:
balandron [24]3 years ago
4 0
The picture is blurry
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HELP FIRST GETS BRAINLY
TiliK225 [7]

Answer:

3/21 most simplest form is 1/7

Step-by-step explanation:

4 0
3 years ago
Find the area of each shape. Show your reasoning.
Troyanec [42]

Answer:

Those areas are: A 1 = 12,  A 2 = 19

Step-by-step explanation:

The area of shape 1  : it consists of 1 square + 4 right triangles

Area of the square: A = a², area of the triangle: A = 1/2 · a · h

A 1 = 2² + 4 · 1/2 · 2 · 2 = 4 + 8 = 12

The area of shape 2 :  it consists of 2  isosceles triangles

A 2 = 1/2 · 2 · 4 + 1/2 · 6 · 5 = 4 + 15 = 19

3 0
4 years ago
Kasey has 8 packages of gelatin. She plans to fill molds that each take 1 1/3 packages of gelatin. Each mold can be divided into
Ipatiy [6.2K]

if in total Kasey has 8 packaged of gelatin and it takes 1 1/3 for each mold which equals 6 servings than you could work it out as

8 divided by 1 1/3=6.015 since its not a whole number than you'd want to go down to just 6 resulting in Kasey creating 6 molds

6 molds times 6 servings= 36 servings

6 0
4 years ago
Look at this cylinder:
Sedbober [7]
  • Height=h=8cm
  • Radius=r=4cm

We know

\boxed{\sf \star TSA_{(Cylinder)}=2\pi r(h+r)}

\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=2\times \dfrac{22}{7}\times 4(8+4)

\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{176}{7}(12)

\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{2112}{7}

\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=301.7cm^2

Now

  • New Radius=2(4)=8cm
  • New Height=2(8)=16cm

\\ \sf\longmapsto TSA_{(New\:Cylinder)}=2\times \dfrac{22}{7}\times 8(16+8)

\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{352}{7}(24)

\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{8448}{7}

\\ \sf\longmapsto TSA_{(New\:Cylinder)}=1204.7cm^2

So

\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{1204.7}{301.7}

\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{4}{1}

\\ \sf\longmapsto\underline{\boxed{\bf{ {TSA_{(New\:Cylinder)}}:{TSA_{(Old\:Cylinder)}}=4:1}}}

Hence our correct option is Option C

6 0
3 years ago
What is the solution for this problem 3p-1=5(p-1)-2(7-2p)
qwelly [4]

______________

3p-1=5(p-1)-2(7-2p)

3p-1=5p-5-14+4p

3p-1=9p-19

6p=18

p=18/6

p=3

____________

4 0
3 years ago
Read 2 more answers
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