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Margarita [4]
3 years ago
10

An 8 cm cube is cut into several small cubes of edge 2cm.how many cubes are formed ​

Mathematics
1 answer:
LiRa [457]3 years ago
6 0
Its 8
not sure how to show the work but drew a pic and its 8
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You read 40 pages a night for x amount what is the expression that represints the numbr of nights
dalvyx [7]
This depends on how many pages you read all together. I don't fully understand what the question is that you are asking. Could you try to explain it a little bit more? If you can then I could probably help you out :)
3 0
4 years ago
Solve the equation for x<br><br> 5(x-3)+2x=4(x+3)
Tamiku [17]

x = 9

Step-by-step explanation:

5x - 15 + 2x = 4x + 12

7x - 4x = 12 + 15

3x = 27

x = 9

8 0
3 years ago
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Solve the equation for x.<br><br> 6x = –54
Romashka [77]

Divide each term by 6 and simplify.

x = −9

4 0
3 years ago
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Emilia has a bag of colored marbles. The bag contains the same ratio of red marbles to blue marbles as the ratio of green marble
scoray [572]
Red =18
blue=48
green=12
orange=?
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8 0
3 years ago
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A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


6 0
4 years ago
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