2 years ago

Please help me out its due tmr :/

Chemistry

1 answer:

lesantik [10]2 years ago

7 0

Answer:

using this for points, did you get the answer because I can try and help?

Explanation:

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Yakvenalex [24]

Answer:

75,900 g

Explanation:

m=d×v

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3 years ago

5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure water?

Margaret [11]

Answer:

$\boxed {\boxed {\sf 2.8 \ m }}$

Explanation:

The formula for molality is:

$m=\frac{moles \ of \ solute}{kg \ of \ solvent}$

There are 0.210 moles of KBr and 0.075 kilograms of pure water.

$moles= 0.210 \ mol \\kilograms = 0.075 \ kg$

Substitute the values into the formula.

$m= \frac{ 0.210 \ mol }{0.075 \ kg}$

Divide.

$m= 2.8 \ mol/kg= 2.8 \ m$

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2 years ago

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Mariulka [41]

Answer:

See below.

Explanation:

pH = - log (H+)

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If you convert the other units to the form 1 x 10^-n then the pH will be n.

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The answer I believe is genus

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The reaction type represented by AB ---> A + B is known as

nordsb [41]

Answer:

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Explanation:

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