Answer:
Mass of MgO = 36.27 g
Mg produced less number of moles of MgO it will act as limiting reactant while oxygen is present is in excess.
Explanation:
Given data:
Number of moles of Mg = 0.9 mol
Number of moles of O₂ = 1.1 mol
Number of moles of MgO = ?
Which reactant is in excess = ?
Which one is limiting reactant = ?
Solution:
Chemical equation:
2Mg + O₂ → 2MgO
now we will compare the moles of MgO with oxygen and magnesium.
Mg : MgO
2 : 2
0.9 : 0.9
O₂ : MgO
1 : 2
1.1 : 2/1×1.1 = 2.2
Mg produced less number of moles of MgO it will act as limiting reactant while oxygen is present is in excess.
Mass of MgO:
Mass = number of moles × molar mass
Mass = 0.9 mol × 40.3 g/mol
Mass = 36.27 g
