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Chemistry

1 answer:

zaharov [31]3 years ago

3 0

Answer:

Mass of MgO = 36.27 g

Mg produced less number of moles of MgO it will act as limiting reactant while oxygen is present is in excess.

Explanation:

Given data:

Number of moles of Mg = 0.9 mol

Number of moles of O₂ = 1.1 mol

Number of moles of MgO = ?

Which reactant is in excess = ?

Which one is limiting reactant = ?

Solution:

Chemical equation:

2Mg + O₂ → 2MgO

now we will compare the moles of MgO with oxygen and magnesium.

Mg : MgO

2 : 2

0.9 : 0.9

O₂ : MgO

1 : 2

1.1 : 2/1×1.1 = 2.2

Mg produced less number of moles of MgO it will act as limiting reactant while oxygen is present is in excess.

Mass of MgO:

Mass = number of moles × molar mass

Mass = 0.9 mol × 40.3 g/mol

Mass = 36.27 g

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. What is a carbonyl group? Draw the carbonyl groups that are characteristic of aldehydes, ketones, carboxylic acids, and esters

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Answer :

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The general formula of carboxylic is, $C_nH_{2n+1}COOH$ . According to the IUPAC naming, the carboxylic are named as alkanoic acids.

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The general representation of aldehyde is, $R-CHO$ . According to the IUPAC naming, the aldehyde are named as alkanals.

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The general representation of ketone is, $R-CO-R^'$ . According to the IUPAC naming, the ketone are named as alkanone.

Ester group : It is the class of organic compound in which the (-COO) group is directly attached to the two alkyl group of carbon is known as ester.

The general representation of ester is, $R-COO-R^'$ . According to the IUPAC naming, the ester are named as alkyl alkanoate.