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2 years ago

Plssss help asapp will give brainliest!!!

Chemistry

1 answer:

zaharov [31]2 years ago

3 0

Answer:

Mass of MgO = 36.27 g

Mg produced less number of moles of MgO it will act as limiting reactant while oxygen is present is in excess.

Explanation:

Given data:

Number of moles of Mg = 0.9 mol

Number of moles of O₂ = 1.1 mol

Number of moles of MgO = ?

Which reactant is in excess = ?

Which one is limiting reactant = ?

Solution:

Chemical equation:

2Mg + O₂ → 2MgO

now we will compare the moles of MgO with oxygen and magnesium.

Mg : MgO

2 : 2

0.9 : 0.9

O₂ : MgO

1 : 2

1.1 : 2/1×1.1 = 2.2

Mg produced less number of moles of MgO it will act as limiting reactant while oxygen is present is in excess.

Mass of MgO:

Mass = number of moles × molar mass

Mass = 0.9 mol × 40.3 g/mol

Mass = 36.27 g

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The given sentence is part of a longer question.

I found this question with the same sentence. So, I will help you using this question:

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