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Sonja [21]
3 years ago
13

What would be the effect of abundant atp on the citric acid cycle?

Chemistry
1 answer:
maxonik [38]3 years ago
6 0

ATP binds at the allosteric regulatory site of the enzyme that combines acetyl CoA and oxaloacetate and slows the citric acid cycle. ATP can function as an allosteric regulator of the citric acid cycle.

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Aqueous solutions of isopropyl alcohol are commonly sold as rubbing alcohol. The boiling point of isopropyl alcohol is 82.4 °C.
Monica [59]

Answer:

This is due to more hydrogen bonding in ethylene glycol than it is in isopropyl alcohol

Explanation:

The boiling point of isopropyl alcohol is 82.4 °C it contains only a single OH group, hence intermolecular hydrogen bonding is solely responsible for it's boiling point, whereas Ethylene glycol (CH2OHCH2OH) contains 2-OH group and both intermolecular and intramolecular hydrogen bonding are responsible for the higher boiling point of ethylene glycol at 198 °C.

8 0
3 years ago
What is the difference between a crystalline material and an amorphous material? Give an example of each type.
Igoryamba

Answer :

As we know that there are two types of solids.

(1) Amorphous Solids

(2) Crystalline Solids

Amorphous Solids : It is a type of solids in which the constituent particles of the matter are arranged in the random manner.

That means there is no proper arrangement of atoms in solid lattice but the atoms or molecules are closely spaced that means they can move freely from one place to another.

The examples of amorphous solid are, plastics, glass, rubber, metallic glass, polymers, gel, fused silica, pitch tar, thin film lubricants, wax.

Crystalline Solids : It is a type of solids where the constituent particles of the matter are arranged in the specific manner.

That means there is a proper arrangement of atoms in solid lattice. They do not have space between the molecules or atoms and they can not move freely from one place to another.

The examples of crystalline solids are, quartz, calcite, sugar, mica, diamonds, snowflakes, rock, calcium fluoride, silicon dioxide, alum.

7 0
3 years ago
10.0 mL of 0.0400 M KBrO3 and 10.0 mL 0.100 M HCl is mixed with 10.0 mL of 0.0100 M KI, 10.0 mL 0.00100 M Na2S2O3, 1.0 mL of sta
Oliga [24]

Answer:

0.0196

Explanation:

The Total volume of the solution = Volume of (KBrO_3 + HCl + KI +Na_2S_2O_3 + Starch + H_2O)

= 10 mL + 10 mL + 10 mL+ 10 mL + 1 mL + 10 mL

= 51 mL

The concentration of  [H^+] = \dfrac{ mL \ used \times 0.1 \ M}{total \ volume}

= \dfrac{10 \ mL \times 0.1 M}{51 \ mL}

= 0.0196

5 0
3 years ago
The pressure 75.0 meters underwater is 837 kpa. What is this pressure in mmhg
spin [16.1K]
<h3>Answer:</h3>

                 6278 mmHg

<h3>Explanation:</h3>

Kilopascal (kPa) and Millimeter of Mercury (mm Hg) are both the units of Pressure. In medical science the pressure is often measured in mm of Hg.

Also,

                 0.133322387415 kPa equals  =  1 mmHg equals

Then,

                       837 kpa will be equal to  =  X mmHg

Solving for X,

                     X =  (837 kPa × 1 mmHg) ÷ 0.133322387415 kPa

                     X  =  6278.0153898 mmHg

Or when rounded to 4 significant numbers,

                     X  =  6278 mmHg

7 0
3 years ago
how much alum product would be lost to the crystallization solution if you had 42.5 ml of solution after filtration and the solu
JulsSmile [24]

Answer:

Total amount of alum lost = 0.5122 grams

Explanation:

Let the total volume of the solution be 100 mL

In 100 mL of solution, there is 2.63 gram of alum.

Out of this 100 mL solution, 42.5 mL is remaining.

Amount of alum in 42.5 mL solution is

\frac{42.5}{100} * 2.63 = 1.117\\ grams

Now the amount of alum lost is 2.63 -1.117 = 0.5122 grams

3 0
3 years ago
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