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TiliK225 [7]
3 years ago
12

ОА H+ HH O H+ H → He Oc He+ TH Не ODH + Η >

Chemistry
1 answer:
iren [92.7K]3 years ago
4 0

Ao H+HH OH

santa said he will eat shower curtian at 2 am

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Manganese dioxide (MnO2(s), Hf = –520.0 kJ) reacts with aluminum to form aluminum oxide (AI2O3(s), Hf = –1699.8 kJ/mol) and mang
Temka [501]

Answer : The enthalpy of the reaction = -1839.6 KJ

Solution : Given,

\Delta (H_{f})_{MnO_{2}} = -520.0 KJ/mole

\Delta (H_{f})_{Al_{2}O_{3}} = -1699.8 KJ/mole

The balanced chemical reaction is,

3MnO_{2}(s)+4Al(s)\rightarrow 2Al_{2}O_{3}(s)+3Mn(s)

Formula used :

\Delta (H_{f})_{reaction}=\sum n(\Delta H_{f})_{product}-\sum n(\Delta H_{f})_{reactant}

\Delta (H_{f})_{reaction}=(2\times \Delta H_{Al_{2}O_{3}(s)}+3\times \Delta H_{Mn(s)} )-(3\times \Delta H_{MnO_{2}(s) }+4\times\Delta H_{Al}(s))

We know that the standard enthalpy of formation of the element is equal to Zero.

Therefore, the enthalpy of formation of (Mn) and (Al) is equal to zero.

Now, put all the values in above formula, we get

\Delta (H_{f})_{reaction}=[2moles\times (-1699.8 KJ/mole)}+3moles\times (0\text{ KJ/mole}})]-[(3moles\times(-520.0KJ/mole }+4moles\times(0\text{ KJ/mole})]

                        = (-3399.6) + (1560)

                        = -1839.6 KJ



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3 years ago
A car is moving with the velocity of 20m/s. After 5 seconds it's velocity becomes 50m/s. Find its acceleration.​
irinina [24]

Answer:

6 m/s^2

Explanation:

a= (v2 - v1)/t

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                                                H₃C-CH₂-CH₂-CH₃

Now, replace one hydrogen on terminal carbon with -OH group and convert it into Butanol.

                                                H₃C-CH₂-CH₂-CH₂-OH

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