What is the specific heat of aluminum?
The specific heat of aluminum is 0.90J/g°C.
Given:
Heat absorbs = 677 J
Mass of the substance = 10 g
Initial temperature = 50°C
Final temperature = 125°C
Formula used:
Q = m x c x ΔT
which can also be written as,
Q = m x c x ( 
- 
)
where,
Q = heat absorbs
m = mass of a substance
c = heat capacity of aluminum
= Final temperature
= Initial temperature
Now, put all the values in the formula given above to get the specific heat of aluminum,
677g = (10g) x c x (125 - 50)°C
c = 0.9026 J/g°C
c = 0.90 J/g°C
Learn more about the specific heat of aluminum here,
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Answer:
There are no units with electro negativity. Linus Pauling designed a scale of electro negativity that ranks elements with respect to each other. So, for example, fluorine is a 4.0 in comparison to 0.7 for francium.
Explanation:
Missing question: <span>What will happen if we combine the solution of sodium iodide and the solution of lead(II) nitrate?
Chemical reaction 1: Pb(NO</span>₃)₂(s) → Pb²⁺(aq) + 2NO₃⁻(aq).
Chemical reaction 2: 2NaI(aq) + Pb(NO₃)₂(aq) → PbI₂(s) + 2NaNO₃(aq).
Ionic reaction:
2Na⁺(aq) + 2I⁻(aq) + Pb²⁺(aq) + 2NO₃⁻(aq) → PbI₂(s) + 2Na⁺(aq) + 2NO₃⁻(aq).
Net ionic reaction: 2I⁻(aq) + Pb²⁺(aq) → PbI₂(s).
Yes we could by testing bombs and many other nuclear testing
The volume did not change, it remained at 20 ml
<h3>Further explanation</h3>
Given
20 ml a sample gas at STP(273 K, 1 atm)
T₂=546 K
P₂=2 atm
Required
The volume
Solution
Combined gas Law :
Input the value :
The volume does not change because the pressure and temperature are increased by the same ratio as the initial conditions (to 2x)
