Answer:
a = 2 [m/s^2]
Explanation:
To solve this problem we must use the expressions of kinematics, we must bear in mind that when a body is at rest its velocity is zero.
where:
Vf = final velocity = 0
Vi = initial velocity = 60 [m/s]
a = desacceleration [m/s^2]
t = time = 30 [s]
Note: the negative sign of the above equation means that the car is slowing down, i.e. its speed decreases.
0 = 60 - (a*30)
a = 2 [m/s^2]
Answer:
La rapidez con que el fármaco es absorbido en el torrente sanguíneo depende, en parte, del suministro de sangre al músculo: cuanto menor sea el aporte de sangre, más tiempo necesitará el fármaco para ser absorbido.
Para la administración por vía intravenosa se inserta una aguja directamente en una vena
Explanation:
Answer:<em> Option (D) is correct.</em>
Explanation:
Considering the hypothesis elaborated in this comprehension, it's given that areas that tend to lie near forest fires usually have extra positive strikes since smoke carries positively charged particles. In rudimentary term, this states that occurrence of positively charged particles will result in extra positive strikes.
Option (D) states that occurrence of extra positive strikes will be there even weeks after the charge of smoke particles have been dissociated.
Therefore this option, most seriously undermines the hypothesis.
Answer:
Angular acceleration, 
Explanation:
It is given that,
Mass of the solid sphere, m = 245 g = 0.245 kg
Diameter of the sphere, d = 4.3 cm = 0.043 m
Radius, r = 0.0215 m
Force acting at a point, F = 0.02 N
Let 
is its angular acceleration. The relation between the angular acceleration and the torque is given by :
I is the moment of inertia of the solid sphere
For a solid sphere, 
So, its angular acceleration is 
. Hence, this is the required solution.
Answer:
A. 2.8 m/s
Explanation:
Suppose that at the height of 0 m, the path of the pendulum is lowest.
If we use law of conservation of energy, the pendulum will have zero kinetic energy or K.E when it is at highest point, because K.E happens during movement of object and at the highest point all the energy will be P.E
P.E= mgh
Similarly, when the pendulum reaches at the lowest point, the height becomes zero and the P.E also becomes zero. Now all the energy will be K.E
K.E= 1/2 m v^2
In question, we are asked about the speed as the pendulum it reaches the lowest point of its path. Like we mentioned P.E will be zero at lowest point because of zero height. And also we will use law of conservation of energy because no energy has been lost from system.
K.E= P.E
1/2 m v^2 = mgh
Taking sq.root at both sides
v= Under root 2 gh
v=Under root 2x 9.8 m/s x0.4 m
v=Under root 7.84
v=2.8 m/sec
Hope it helps!
