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lidiya [134]
3 years ago
13

A concrete highway is built of slabs 12 m long (20°C). How wide should the expansion cracks between the slabs be (at 20°C) to pr

event buckling if the range of temperature is -30° to +50°C? (12 x 10⁻⁶ °C⁻¹ for concrete)
Physics
1 answer:
Bezzdna [24]3 years ago
5 0

Answer:

0.001152m

Explanation:

Linear expansivity of a material is the change in length of the material per unit length per degree rise in temperature. Mathematically,

¢ = ∆L/L1∆°C

¢ is the linear expansivity of the material = 12 x 10⁻⁶ °C⁻¹

Where ∆L is the change in length = L2-L1

L2 is the final length = ?

L1 is the initial length = 12m

∆°C is the change in temperature = °C2 - °C1 = 50-(-30) = 80°C

Substituting this values inside the formula to get the final length L2 after expansion, we have;

12 x 10⁻⁶ °C⁻¹ = L2-12/12×80

12 x 10⁻⁶ °C⁻¹ = L2-12/960

L2-12= 960×12 x 10⁻⁶ °C⁻¹

L2-12 = 0.001152

L2 = 12+0.001152

L2 = 12.001152m

Expansion will be the change in length L2-L1 = 12.001152-12

= 0.001152m

The expansion cracks between the slabs should be 0.001152m wide to prevent buckling

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Answer:

D

Explanation:

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so Δv=5000 m/sec

a=Δv/Δt

=5000/10

a=500 m/sec²                 as 500÷1000=0.5 Km

a=0.5 km/sec²

so D is the right answer.

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A plane moves at a certain velocity and then it accelerates at the rate of 52m/s for a distance of 2300m to reach a velocity of
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6 0
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A radio station transmits waves at a frequency of 120MHz an a speed of 300 million m/s. Calculate the wavelength.
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Light enters an equilateral prism with an incident angle of 35° to the normal of the surface. Calculate the angle at which the
julia-pushkina [17]

Answer:

65.9°

Explanation:

When light goes through air to glass

angle of incidence, i = 35°

refractive index, n = 1.5

Let r be the angle of refraction

Use Snell's law

n=\frac{Sini}{Sinr}

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Now the ray is incident on the glass surface.

A = r + r'

Where, r' be the angle of incidence at other surface

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Now use Snell's law at other surface

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Where, i' be the angle at which the light exit from other surface.

\frac{1}{1.5}=\frac{Sin37.5'}{Sini'}

Sin i' = 0.913

i' = 65.9°

4 0
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