A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

$\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]$

The inverse of the matrix is

$\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]$

So, the Inverse Transformation is given by

$T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$

So, no option is correct. And the answer is

$T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$

Learn more about linear transformations here-

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5 0

2 years ago

Please help asap! thx

vovikov84 [41]

Answer:

y = 0

Step-by-step explanation:

The given sinusoidal equation is $y = 2 \cdot sin \left(\dfrac{\pi}{2} \cdot x + 3 \right)$

The general form of the sin function is presented as follows;

y = A·sin(B·(x - C)) + D

Where;

A = The amplitude

The period, T = 2·π/B

The frequency, f = B/2·π

C = The horizontal shift

D = The vertical shift

By comparison with the given sine function, we have;

The amplitude, A = 2

The frequency, f = B/2·π = π/2/(2·π) = 1/4

The frequency, f = 1/4 Hz

C = The horizontal shift = 3/(π/2) = 6/π

The vertical shift, D = 0

Given that the mid line of the parent function, sin(x), is the line y = 0, and that the vertical shift is 0, the midline of the function, $y = 2 \cdot sin \left(\dfrac{\pi}{2} \cdot x + 3 \right)$ , is therefore, the line;

y = 0.

3 0

3 years ago

Bottom#4<br> Which value represents the median from the box and whisker plot attached?

Andreyy89

Answer:

Step-by-step explanation:

the median is the line inside the box which is 84

8 0

4 years ago