Remember you can do anything to an equation as long as you do it to both sides
and when multiply by negative, flip sign
8+h>2+3h
minus h both sides
8+h-h>2+3h-h
8+0>2+2h
8>2+2h
minus 2 both sides
8-2>2-2+2h
6>0+2h
6>2h
divide by 2 both sides
6/2>2h/2
3>1h
3>h
first opotin
Answer:
- 109°, obtuse
- 131°, obtuse
- 53°, acute
- 124°, obtuse
Step-by-step explanation:
You are exected to know the relationships of angles created where a transversal crosses parallel lines.
- Corresponding angles are equal (congruent).
- Adjacent angles are supplementary, as are any linear pair.
- Opposite interior (or exterior) angles are equal (congruent).
The appearance of the diagram often gives you a clue.
You also expected to know the name (or category) of angles less than, equal to, or greater than 90°. Respectively, these are <em>acute</em>, <em>right</em>, and <em>obtuse</em> angles.
1. Adjacent angles are supplementary. The supplement of the given angle is 109°, so x will be obtuse.
2. Opposite exterior angles are equal, so y will be 131°. It is obtuse.
3. Opposite interior angles are equal, so w will be 53°. It is acute.
4. Corresponding angles are equal, so x will be 124°. It is obtuse.
Question 8 measurements. Angle H (acute) Angle M (obtuse) Angle K (acute)
Question 9 measurements. Angle P (right) Angle Q (obtuse) Angle R (acute) Angle S (obtuse) Angle T (right)
X=36.... because 17-36=19
Hello,
If we want to factor the expression, we have to solve
3x² + 10x + 8 = 0
a = 3 ; b = 10 ; c = 8
∆ = b² - 4ac = 10² - 4 × 3 × 8 = 4 > 0
x1 = (-b - √∆)/2a = (-10 - 2)/6 = -12/6 = -2
x2 = (-b + √∆)/2a = (-10 + 2)/6 = -8/6 = -4/3
Factor :
a (x - x1)(x - x2)
= 3(x + 2)(x + 4/3)
= (x + 2)(3x + 4)
